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Separable differential equations and families of solutionsEdexcel International A Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel International A Level Further Maths

Separable differential equations and families of solutions

Total 27 marks

Name

Class

Date

  1. 1
    A curve CC passes through the point (0,3)(0,3) and satisfies the differential equation dydx=2xy\frac{dy}{dx}=2xy, where y>0y>0.
    (a)
    Which of the following is the general solution of the differential equation?
    [1 mark]
    • Ay=Aex2y=Ae^{x^2}
    • By=ex2+Ay=e^{x^2}+A
    • Cy=Ae2xy=Ae^{2x}
    • Dy=Ax2y=Ax^2
    (b)
    Find the value of yy on CC when x=1x=1.
    [1 mark]
    • Ae3e^3
    • B3+e3+e
    • C3e23e^2
    • D3e3e
    (c)
    Show that CC has a minimum point at (0,3)(0,3).
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A drink cools in a room at a constant temperature of 20 ∘C20\,^\circ\text{C}. At time tt minutes its temperature is θ ∘C\theta\,^\circ\text{C}, and the rate of decrease of θ\theta is proportional to θ−20\theta-20, with constant of proportionality k>0k>0. Initially θ=80\theta=80.
    (a)
    Which differential equation models the cooling?
    [1 mark]
    • Adθdt=k(θ−20)\frac{d\theta}{dt}=k(\theta-20)
    • Bdθdt=−kθ\frac{d\theta}{dt}=-k\theta
    • Cdθdt=−k(θ−20)\frac{d\theta}{dt}=-k(\theta-20)
    • Ddθdt=−kθ−20\frac{d\theta}{dt}=-\frac{k}{\theta-20}
    (b)
    Solve the differential equation to find θ\theta in terms of tt and kk.
    [1 mark]
    • Aθ=20+80e−kt\theta=20+80e^{-kt}
    • Bθ=20+60e−kt\theta=20+60e^{-kt}
    • Cθ=60+20e−kt\theta=60+20e^{-kt}
    • Dθ=20+60ekt\theta=20+60e^{kt}
    (c)
    After 55 minutes the temperature is 50 ∘C50\,^\circ\text{C}. Find the exact value of kk.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A curve satisfies the differential equation dydx=xe−y\frac{dy}{dx}=xe^{-y}.
    (a)
    Find the general solution, giving eye^y in terms of xx.
    [3 marks]
    (b)
    Given that y=0y=0 when x=0x=0, find yy in terms of xx. State the equation of the line of symmetry of the curve and the coordinates of its minimum point.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A curve CC passes through the point (1,1)(1,1) and, for x>0x>0, satisfies the differential equation xdydx=y2x\frac{dy}{dx}=y^2.
    (a)
    Solve the differential equation to find yy in terms of xx.
    [6 marks]
    (b)
    Describe the graph of y=11−ln⁡xy=\frac{1}{1-\ln x} for x>0x>0, x≠ex\neq e. Give the gradient at (1,1)(1,1), the equations of both asymptotes, where yy is positive and where it is negative, and the behaviour as x→0+x\to0^+ and as x→ex\to e from either side.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).