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De Moivre's theorem and trigonometric identitiesEdexcel International A Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel International A Level Further Maths

De Moivre's theorem and trigonometric identities

Total 27 marks

Name

Class

Date

  1. 1
    A complex number is z=cos⁡θ+isin⁡θz=\cos\theta+i\sin\theta, where θ\theta is real.
    (a)
    Find z−3z^{-3}.
    [1 mark]
    • Acos⁡3θ+isin⁡3θ\cos3\theta+i\sin3\theta
    • Bcos⁡3θ−isin⁡3θ\cos3\theta-i\sin3\theta
    • C−cos⁡3θ−isin⁡3θ-\cos3\theta-i\sin3\theta
    • Dcos⁡θ3−isin⁡θ3\cos\frac\theta3-i\sin\frac\theta3
    (b)
    Find z4+z−4z^4+z^{-4}.
    [1 mark]
    • A2isin⁡4θ2i\sin4\theta
    • B2cos⁡4θ2\cos^4\theta
    • C2cos⁡4θ2\cos4\theta
    • D22
    (c)
    Given that θ=π9\theta=\frac\pi9, find z6z^6 in the form a+iba+ib, giving exact values of aa and bb.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Let c=cos⁡θc=\cos\theta and s=sin⁡θs=\sin\theta, and consider (c+is)3(c+is)^3 expanded using the binomial theorem.
    (a)
    Which expression is the real part of (c+is)3(c+is)^3?
    [1 mark]
    • Ac3−3cs2c^3-3cs^2
    • Bc3+3cs2c^3+3cs^2
    • C3c2s−s33c^2s-s^3
    • Dc3−3c2sc^3-3c^2s
    (b)
    Which expression equals sin⁡3θ\sin3\theta in terms of sin⁡θ\sin\theta only?
    [1 mark]
    • A3sin⁡θ+4sin⁡3θ3\sin\theta+4\sin^3\theta
    • B4sin⁡θ−3sin⁡3θ4\sin\theta-3\sin^3\theta
    • C3sin⁡θ−4sin⁡2θ3\sin\theta-4\sin^2\theta
    • D3sin⁡θ−4sin⁡3θ3\sin\theta-4\sin^3\theta
    (c)
    Hence express cos⁡3θ\cos3\theta in terms of cos⁡θ\cos\theta only.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    De Moivre's theorem states that (cos⁡θ+isin⁡θ)n=cos⁡nθ+isin⁡nθ(\cos\theta+i\sin\theta)^n=\cos n\theta+i\sin n\theta for every integer nn. A student proves the case n≥1n\ge1 by induction.
    (a)
    Show that if the result is true for n=kn=k, where k≥1k\ge1, then it is true for n=k+1n=k+1.
    [3 marks]
    (b)
    Prove that the result is also true for n=−mn=-m, where mm is a positive integer.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Throughout, z=cos⁡θ+isin⁡θz=\cos\theta+i\sin\theta, c=cos⁡θc=\cos\theta and s=sin⁡θs=\sin\theta.
    (a)
    Show that cos⁡5θ=16cos⁡5θ−20cos⁡3θ+5cos⁡θ\cos5\theta=16\cos^5\theta-20\cos^3\theta+5\cos\theta.
    [6 marks]
    (b)
    By considering (z−1z)4\left(z-\dfrac1z\right)^4, show that sin⁡4θ=18(cos⁡4θ−4cos⁡2θ+3)\sin^4\theta=\frac18(\cos4\theta-4\cos2\theta+3), and hence find ∫0π/2sin⁡4θ dθ\displaystyle\int_0^{\pi/2}\sin^4\theta\,d\theta.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).