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Chirality and optical isomerismEdexcel International A Level Chemistry: Revision notes

Section 1

Chiral centres

A chiral centre (asymmetric carbon atom) is a carbon atom bonded to four different groups. A molecule with one chiral centre can exist in two forms that cannot be superimposed on each other. This is optical isomerism, a type of stereoisomerism.

Example: in lactic acid, CH₃CH(OH)COOH, C2 has H, CH₃, OH and COOH attached, so it is chiral. In propan-2-ol, the central carbon has two identical CH₃ groups, so it is not chiral.

To identify a chiral centre, check each carbon bonded to four groups and ask if all four are different.

Key termschiral centreoptical isomerism
Common mistake

Calling a carbon chiral because it is bonded to four groups. All four must be different, and a C=O or C=C carbon is never chiral.

Section 2

Enantiomers and 3D diagrams

The two optical isomers are called enantiomers. They are object and non-superimposable mirror images, like left and right hands.

Draw them in 3D: the chiral carbon at the centre, two bonds in the plane of the paper, one bond as a wedge (towards the viewer) and one as a dash (away). The second enantiomer is the mirror image: swap the wedge and dash groups, or reflect across a vertical line.

Enantiomers have the same physical properties (melting point, boiling point, density) and the same chemical reactions with achiral reagents. They differ only in their effect on plane-polarised light and in their reactions with other chiral molecules, such as enzymes.

Key termsenantiomersnon-superimposable
Exam tip

When drawing the second enantiomer, keep the same four groups in the same bonds-in-the-plane positions and swap only the wedge and dash groups.

Section 3

Optical activity and racemic mixtures

Optical activity is the ability of a single enantiomer to rotate the plane of plane-polarised monochromatic light. Plane-polarised light vibrates in only one plane; it is passed through the sample in a polarimeter.

One enantiomer rotates the plane clockwise (+) and the other by an equal angle anticlockwise (−).

A racemic mixture (racemate) contains equal amounts of both enantiomers. The rotations cancel, so it is optically inactive.

Key termsoptical activityplane-polarised lightracemic mixture
Common mistake

Saying a racemic mixture has no chiral molecules. Both enantiomers are present, but their effects cancel.

Section 4

Evidence for SN1 and SN2 mechanisms

If a halogenoalkane that is a single enantiomer is hydrolysed, the optical activity of the product shows the mechanism.

  • SN1 (tertiary halogenoalkanes): the halogen leaves first to give a planar carbocation. OH⁻ attacks from either side with equal probability, giving a racemic mixture, so the product has no optical activity.
  • SN2 (primary and secondary halogenoalkanes): OH⁻ attacks from the side opposite the halogen in one step, through a transition state. The configuration is inverted and only one enantiomer forms, so the product is optically active.

Example: 3-bromo-3-methylhexane (tertiary) gives a racemic product via SN1.

Key termsSN1SN2carbocation
Exam tip

Product optically inactive from a pure enantiomer means SN1; product optically active means SN2.

Section 5

Evidence for addition to carbonyl compounds

Aldehydes and most unsymmetrical ketones react with HCN (with KCN present) to form hydroxynitriles. For example, ethanal gives 2-hydroxypropanenitrile, CH₃CH(OH)CN, which has a chiral centre.

Mechanism: the nucleophile CN⁻ attacks the δ+ carbon, the C=O π bond breaks to give an intermediate anion, and this is protonated by HCN or water.

The carbonyl group is planar, so CN⁻ attacks from either side with equal probability, forming equal amounts of both enantiomers. The product is a racemic mixture and has no optical activity, evidence for the planar structure of the carbonyl carbon.

Key termsnucleophilic additionhydroxynitrile
Common mistake

Saying the product is inactive because it has no chiral centre. It is chiral; it is optically inactive because it is a racemic mixture.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Chirality and optical isomerism

  1. Lactic acid (2-hydroxypropanoic acid), CH₃CH(OH)COOH, is made by muscle cells during hard exercise and by bacteria in yoghurt production.
    Explain why lactic acid shows optical isomerism and what is meant by its optical isomers.2 marks
  2. Ibuprofen, (CH₃)₂CHCH₂C₆H₄CH(CH₃)COOH, is a painkiller that is sold as an equal mixture of its two optical isomers, although only one of them is pharmacologically active. Optical activity is measured in a polarimeter using plane-polarised monochromatic light.
    Explain why the equal mixture of ibuprofen isomers has no effect on plane-polarised light.2 marks
  3. Two samples of halogenoalkane, each consisting of a single optical isomer, are hydrolysed by heating with aqueous sodium hydroxide. Compound X, 3-bromo-3-methylhexane, CH₃CH₂C(CH₃)(Br)CH₂CH₂CH₃, gives an alcohol product that does not rotate the plane of plane-polarised light. Compound Y, 2-bromobutane, gives butan-2-ol that does rotate the plane of plane-polarised light.
    Explain what the result for compound X indicates about the mechanism of its hydrolysis.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).