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Mass spectra and infrared spectroscopyEdexcel International A Level Chemistry: Revision notes

Section 1

Mass spectrometry: molecular ion and fragments

In mass spectrometry a molecule loses an electron to form the molecular ion, M⁺. Its m/z value (mass-to-charge ratio, with charge +1) is the relative molecular mass, and it is the peak with the highest m/z (ignoring tiny isotope peaks).

The molecular ion is unstable and breaks into smaller pieces. Only the positively charged fragments are detected, so a spectrum shows a fragmentation pattern. The base peak is the tallest peak (100% abundance). Fragments are identified from the difference between m/z values: M − 15 is loss of CH₃, M − 17 loss of OH, M − 29 loss of C₂H₅ or CHO.

Key termsmolecular ionm/zfragmentationbase peak

Section 2

Common fragments and deducing structures

Useful fragments:

  • 15: CH₃⁺ · 29: C₂H₅⁺ (or CHO⁺) · 31: CH₂OH⁺ · 43: CH₃CO⁺ or C₃H₇⁺ · 45: COOH⁺ or CH₃CHOH⁺ · 57: C₄H₉⁺ or C₂H₅CO⁺

To deduce a structure: (1) read Mr from M⁺, (2) match it to a molecular formula, (3) assign fragments by subtracting from M, (4) check the proposed structure would break to give those peaks. For example, a strong peak at 43 with M⁺ = 58 and a C=O in the IR spectrum suggests propanone, CH₃COCH₃.

Exam tip

Write fragment ions with a + charge, such as CH₃CO⁺. A formula without the charge does not score.

Section 3

Infrared spectroscopy

Bonds absorb infrared radiation at frequencies that make them vibrate (stretch). Absorptions are quoted as wavenumbers in cm⁻¹, and the data booklet gives ranges:

  • O–H in alcohols: about 3200–3550, broad
  • O–H in carboxylic acids: about 2500–3300, very broad
  • N–H in amines: about 3300–3500
  • C–H: alkanes and alkenes about 2850–3100; aldehydes about 2700–2900
  • C=O: about 1680–1750, strong and sharp
  • C=C: about 1620–1680
  • C–X (halogenoalkanes): below about 1000, in the fingerprint region (for example C–Cl about 600–800 cm⁻¹)

A spectrum shows which bonds, and so which functional groups, are present.

Key termswavenumberinfrared spectroscopy
Common mistake

A carboxylic acid has both a very broad O–H absorption and a C=O absorption. An alcohol has no C=O absorption. Always check for both.

Section 4

Combining IR and mass spectra

Use both techniques together:

  1. The molecular ion gives Mr and a molecular formula.
  2. IR shows the functional groups (O–H, C=O, C=C, N–H).
  3. Fragments show how the carbon skeleton is arranged, to choose between isomers.

Example: Mr 60, broad 3200–3550 cm⁻¹, no C=O and a base peak at 45 suggest propan-2-ol; propan-1-ol would give a peak at 31 (CH₂OH⁺).

Key termsisomer

Section 5

Core Practical 8: analysis of unknowns

Identify inorganic and organic unknowns by systematic tests and record observations.

Inorganic: flame tests for cations; carbonate (acid gives CO₂); sulfate (barium chloride); halide (silver nitrate, then dilute and concentrated ammonia); ammonium (warm with sodium hydroxide; ammonia turns damp red litmus blue).

Organic: alkene (bromine water decolourised); alcohol (PCl₅ steamy fumes); aldehyde (Fehling's or Benedict's brick-red precipitate; dichromate orange to green); carboxylic acid (effervescence with carbonate); halogenoalkane (hydrolysis then silver nitrate in ethanol).

Record each observation and the conclusion it supports.

Must know

  • The molecular ion peak (highest m/z) gives Mr
  • Fragment ions are positively charged; identify them from the m/z differences
  • Carboxylic acids: very broad O–H plus C=O; alcohols: broad O–H, no C=O
  • C=O about 1680–1750 cm⁻¹ and C=C about 1620–1680 cm⁻¹
  • Combine Mr, IR bands and fragments to deduce a structure

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Mass spectra and infrared spectroscopy

  1. A compound X contains carbon, hydrogen and oxygen only. Its mass spectrum has a molecular ion peak at m/z 58, the largest fragment peak at m/z 43, a small peak at m/z 15 and no significant peak at m/z 29. Its infrared spectrum has a strong absorption at 1715 cm⁻¹ and no absorption above 3000 cm⁻¹.
    Give the formulae of the ions responsible for the peaks at m/z 43 and m/z 15.2 marks
  2. A liquid Z has an infrared spectrum with a very broad absorption between 2500 and 3300 cm⁻¹ and a strong, sharp absorption at 1710 cm⁻¹. Its molecular ion peak is at m/z 74.
    A student suggests that Z is an alcohol. Use the infrared data to explain why this is not correct.2 marks
  3. A compound W contains only carbon, hydrogen and oxygen. Its mass spectrum has peaks at m/z 74, 57, 45 and 29, with the peak at m/z 74 the molecular ion. Its infrared spectrum has a very broad absorption at 2500 to 3300 cm⁻¹ and a strong absorption at 1710 cm⁻¹.
    Use the infrared data to deduce the functional group in W and state the evidence for it.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).