Amino acids and proteinsEdexcel International A Level Chemistry: Revision notes
Section 1
Structure of an amino acid
An amino acid has both an amine group, –NH₂, and a carboxylic acid group, –COOH. In the 2-amino acids found in proteins both are attached to the same carbon, giving the general formula RCH(NH₂)COOH. Glycine has R = H, alanine R = CH₃. The two groups mean an amino acid can behave as both an acid and a base.
Section 2
Acid and base behaviour, and zwitterions
The –COOH group can donate H⁺ (acid) and the –NH₂ group can accept H⁺ (base), so amino acids are amphoteric.
- In strong acid: the amine is protonated, giving a cation ⁺H₃NCH(R)COOH.
- In alkali: the acid group loses H⁺, giving an anion H₂NCH(R)COO⁻.
- In neutral solution and in the solid: a zwitterion, ⁺H₃NCH(R)COO⁻, with no overall charge.
Strong electrostatic attractions between zwitterions explain why amino acids are solids with high melting temperatures and are soluble in water.
Examples: H₂NCH₂COOH + HCl → ⁺H₃NCH₂COOH Cl⁻, and H₂NCH₂COOH + NaOH → H₂NCH₂COO⁻Na⁺ + H₂O.
The zwitterion is not the free –NH₂/–COOH form. In neutral conditions write ⁺H₃N and COO⁻.
Section 3
Optical activity
Every amino acid except glycine has a chiral carbon, bonded to four different groups (H, NH₂, COOH and R). It exists as two enantiomers that are non-superimposable mirror images. Each rotates the plane of plane-polarised monochromatic light in opposite directions. A racemic mixture (equal amounts) gives no net rotation. Glycine has two H atoms on the central carbon, so it is not chiral and has no effect on plane-polarised light. Proteins contain only one enantiomer of each amino acid.
Section 4
Peptide bonds
Amino acids join by condensation: the –COOH of one reacts with the –NH₂ of another and water is lost, forming a peptide bond, –CONH–.
Gly + Ala → H₂NCH₂CONHCH(CH₃)COOH + H₂O
The dipeptide still has –NH₂ at one end and –COOH at the other, so it can react further to give a polypeptide. A protein is a long polypeptide. Gly–Ala and Ala–Gly are different dipeptides because the order of joining differs.
Section 5
Core Practical 15: analysing unknowns
Unknown substances are identified by a series of tests, recording observations and ruling out options.
Inorganic:
- Carbonate: add dilute acid; effervescence, CO₂ turns limewater milky.
- Ammonium: add NaOH(aq), warm; NH₃ turns damp red litmus blue.
- Halide: add dilute HNO₃ then AgNO₃(aq); chloride white, bromide cream, iodide yellow precipitate.
- Sulfate: add BaCl₂(aq) with dilute HCl; white precipitate.
- Metal ions: NaOH(aq) gives, e.g., Cu²⁺ pale blue and Fe³⁺ brown precipitates.
Organic:
- Alkene: bromine water decolourised.
- Carbonyl: 2,4-DNPH gives an orange precipitate; aldehydes also give a silver mirror with Tollens' reagent.
- Primary/secondary alcohol or aldehyde: acidified dichromate(VI) goes orange to green.
- Carboxylic acid: effervescence with sodium carbonate.
Glycine gives none of these inorganic results and is identified by elimination.
Always give the reagent, the observation and the conclusion. A flat 'positive result' earns nothing.
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Amino acids and proteins
- Alanine, CH₃CH(NH₂)COOH, is one of the amino acids found in proteins. A student dissolves alanine in water and then changes the pH of the solution by adding acid or alkali.Alanine (Mr = 89) is a solid with a high melting temperature, whereas butanoic acid (Mr = 88) is a liquid at room temperature. Suggest why.2 marks
- Most amino acids found in proteins are chiral. A student has a solution of one pure enantiomer of alanine, CH₃CH(NH₂)COOH, and a solution of glycine, H₂NCH₂COOH, of the same concentration. Each is placed in turn in a polarimeter using monochromatic light.Explain why alanine shows optical isomerism.2 marks
- Glycine, H₂NCH₂COOH, and alanine, CH₃CH(NH₂)COOH, can react together to form peptides.Give the structural formula of the dipeptide formed when the carboxylic acid group of glycine reacts with the amine group of alanine. Name the type of reaction and the small molecule released.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).