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Hyperbolic and trigonometric substitutionsEdexcel International A Level Further Maths: Flashcards

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$\int\frac{dx}{a^2+x^2}$?

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∫dxa2+x2\int\frac{dx}{a^2+x^2}?
1aarctan⁡xa+c\frac1a\arctan\frac xa+c
∫dxa2−x2\int\frac{dx}{\sqrt{a^2-x^2}}?
arcsin⁡xa+c\arcsin\frac xa+c
∫dxa2+x2\int\frac{dx}{\sqrt{a^2+x^2}}?
arsinh⁡xa+c\operatorname{arsinh}\frac xa+c
∫dxx2−a2\int\frac{dx}{\sqrt{x^2-a^2}}?
arcosh⁡xa+c\operatorname{arcosh}\frac xa+c, for x>ax>a
arsinh⁡x\operatorname{arsinh}x in logarithmic form?
ln⁡(x+x2+1)\ln\left(x+\sqrt{x^2+1}\right)
Substitution for a2+x2a^2+x^2?
x=atan⁡θx=a\tan\theta
Substitution for a2−x2\sqrt{a^2-x^2}?
x=asin⁡θx=a\sin\theta
Substitution for a2+x2\sqrt{a^2+x^2}?
x=asinh⁡ux=a\sinh u
Substitution for x2−a2\sqrt{x^2-a^2}?
x=acosh⁡ux=a\cosh u
What must you change after a substitution in a definite integral?
The limits, to values of the new variable.
First step for ∫dxx2+6x+13\int\frac{dx}{\sqrt{x^2+6x+13}}?
Complete the square: (x+3)2+4(x+3)^2+4.
∫dxx2+4x+13\int\frac{dx}{x^2+4x+13}?
13arctan⁡x+23+c\frac13\arctan\frac{x+2}{3}+c
How do you integrate sin⁡2θ\sin^2\theta?
Use sin⁡2θ=12(1−cos⁡2θ)\sin^2\theta=\frac12\left(1-\cos2\theta\right).

Exam questions on Hyperbolic and trigonometric substitutions

  1. A student evaluates integrals of the form ∫dxa2+x2\int\frac{dx}{a^2+x^2} and ∫dxx2±a2\int\frac{dx}{\sqrt{x^2\pm a^2}} using the standard results.
    Find the exact value of ∫03dxx2+9\int_0^3\frac{dx}{\sqrt{x^2+9}} in terms of a natural logarithm.2 marks
  2. Let I=∫dxx2+6x+13I=\int\frac{dx}{\sqrt{x^2+6x+13}}.
    Hence find the exact value of ∫−31dxx2+6x+13\int_{-3}^{1}\frac{dx}{\sqrt{x^2+6x+13}}.2 marks
  3. Let I=∫02dx(x2+4)2I=\int_0^2\frac{dx}{\left(x^2+4\right)^2}.
    Use the substitution x=2tan⁡θx=2\tan\theta to show that I=18∫0π/4cos⁡2θ dθI=\frac18\int_0^{\pi/4}\cos^2\theta\,d\theta.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).