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Locating roots by change of signAQA A-Level Maths: Mind map

The rule
Full argument
Bisection

Change of sign

locating roots of $f(x)=0$

continuousopposite signs
Fails: discontinuity
Fails: no sign change
Exam tips

Exam questions on Locating roots by change of sign

  1. The function f(x)=x3−5x+3f(x)=x^3-5x+3 is continuous for all real xx.
    Show that f(x)=0f(x)=0 has a root between x=0.6x=0.6 and x=0.7x=0.7.2 marks
  2. Two functions are defined for x≠1x\ne1 by f(x)=1x−1f(x)=\frac{1}{x-1} and for all real xx by g(x)=(x−1)2g(x)=(x-1)^2.
    Explain why the change of sign of ff between x=0x=0 and x=2x=2 does not show that f(x)=0f(x)=0 has a root in that interval.2 marks
  3. The equation ex=3xe^x=3x is written as f(x)=0f(x)=0, where f(x)=ex−3xf(x)=e^x-3x.
    Show that f(x)=0f(x)=0 has a root α\alpha in the interval 0.6<x<0.70.6<x<0.7.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).