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De Moivre's theorem and trigonometric identitiesEdexcel International A Level Further Maths: Flashcards

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State De Moivre's theorem.

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State De Moivre's theorem.
(cos⁡θ+isin⁡θ)n=cos⁡nθ+isin⁡nθ(\cos\theta+i\sin\theta)^n=\cos n\theta+i\sin n\theta for any integer nn.
[r(cos⁡θ+isin⁡θ)]n\left[r(\cos\theta+i\sin\theta)\right]^n?
rn(cos⁡nθ+isin⁡nθ)r^n(\cos n\theta+i\sin n\theta)
How is De Moivre's theorem proved for positive integers?
By induction, using the addition formulae for sine and cosine.
How is it extended to negative integers?
(cos⁡θ+isin⁡θ)−m=1cos⁡mθ+isin⁡mθ=cos⁡mθ−isin⁡mθ(\cos\theta+i\sin\theta)^{-m}=\frac{1}{\cos m\theta+i\sin m\theta}=\cos m\theta-i\sin m\theta.
zn+z−nz^n+z^{-n} when z=cos⁡θ+isin⁡θz=\cos\theta+i\sin\theta?
2cos⁡nθ2\cos n\theta
zn−z−nz^n-z^{-n} when z=cos⁡θ+isin⁡θz=\cos\theta+i\sin\theta?
2isin⁡nθ2i\sin n\theta
How do you find cos⁡nθ\cos n\theta in powers of cos⁡θ\cos\theta and sin⁡θ\sin\theta?
Expand (c+is)n(c+is)^n and take the real part.
cos⁡3θ\cos3\theta in terms of cos⁡θ\cos\theta?
4cos⁡3θ−3cos⁡θ4\cos^3\theta-3\cos\theta
sin⁡3θ\sin3\theta in terms of sin⁡θ\sin\theta?
3sin⁡θ−4sin⁡3θ3\sin\theta-4\sin^3\theta
cos⁡5θ\cos5\theta in terms of cos⁡θ\cos\theta?
16cos⁡5θ−20cos⁡3θ+5cos⁡θ16\cos^5\theta-20\cos^3\theta+5\cos\theta
How do you write sin⁡4θ\sin^4\theta in multiple angles?
Expand (z−1z)4=16sin⁡4θ\left(z-\frac1z\right)^4=16\sin^4\theta and pair zk+z−kz^k+z^{-k} terms.
sin⁡4θ\sin^4\theta in multiple angles?
18(cos⁡4θ−4cos⁡2θ+3)\frac18(\cos4\theta-4\cos2\theta+3)
∫0π/2sin⁡4θ dθ\int_0^{\pi/2}\sin^4\theta\,d\theta?
3π16\frac{3\pi}{16}

Exam questions on De Moivre's theorem and trigonometric identities

  1. A complex number is z=cos⁡θ+isin⁡θz=\cos\theta+i\sin\theta, where θ\theta is real.
    Given that θ=π9\theta=\frac\pi9, find z6z^6 in the form a+iba+ib, giving exact values of aa and bb.2 marks
  2. Let c=cos⁡θc=\cos\theta and s=sin⁡θs=\sin\theta, and consider (c+is)3(c+is)^3 expanded using the binomial theorem.
    Hence express cos⁡3θ\cos3\theta in terms of cos⁡θ\cos\theta only.2 marks
  3. De Moivre's theorem states that (cos⁡θ+isin⁡θ)n=cos⁡nθ+isin⁡nθ(\cos\theta+i\sin\theta)^n=\cos n\theta+i\sin n\theta for every integer nn. A student proves the case n≥1n\ge1 by induction.
    Show that if the result is true for n=kn=k, where k≥1k\ge1, then it is true for n=k+1n=k+1.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).