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Core Pure: Differential equationsEdexcel A-Level Further Maths: Topic test

20 questions, 54 marks

Edexcel A-Level Further Maths

Core Pure: Differential equations topic test

Total 54 marks

Name

Class

Date

  1. 1
    Consider the differential equation dydx+2x1+x2y=3x\frac{dy}{dx}+\frac{2x}{1+x^2}y=3x.
    (a)
    Find the integrating factor.
    [1 mark]
    • Aln⁡(1+x2)\ln(1+x^2)
    • B1+x21+x^2
    • C2x1+x2\frac{2x}{1+x^2}
    • De2x\mathrm{e}^{2x}
    (b)
    Which expression is the general solution?
    [1 mark]
    • Ay=32x2+34x4+c1+x2y=\dfrac{\frac32x^2+\frac34x^4+c}{1+x^2}
    • By=32x2+34x4+cy=\frac32x^2+\frac34x^4+c
    • Cy=32x2+c1+x2y=\dfrac{\frac32x^2+c}{1+x^2}
    • Dy=(32x2+34x4+c)(1+x2)y=\left(\frac32x^2+\frac34x^4+c\right)(1+x^2)
    (c)
    Given that y=1y=1 when x=0x=0, find yy in terms of xx.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A buoy floats on a calm sea and bobs vertically. Its displacement xx metres above its equilibrium level at time tt seconds satisfies d2xdt2=−16x\frac{d^2x}{dt^2}=-16x.
    (a)
    What is the period of the motion?
    [1 mark]
    • Aπ8\frac{\pi}{8} s
    • B44 s
    • C8π8\pi s
    • Dπ2\frac{\pi}{2} s
    (b)
    Which expression is the general solution of the equation?
    [1 mark]
    • Ax=Acos⁡16t+Bsin⁡16tx=A\cos16t+B\sin16t
    • Bx=Ae4t+Be−4tx=A\mathrm{e}^{4t}+B\mathrm{e}^{-4t}
    • Cx=Acos⁡4t+Bsin⁡4tx=A\cos4t+B\sin4t
    • Dx=(A+Bt)e4tx=(A+Bt)\mathrm{e}^{4t}
    (c)
    Given that x=0.3x=0.3 and dxdt=2.4\frac{dx}{dt}=2.4 when t=0t=0, find the amplitude of the motion.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Consider the differential equation d2ydx2+6dydx+9y=5e−x\frac{d^2y}{dx^2}+6\frac{dy}{dx}+9y=5\mathrm{e}^{-x}.
    (a)
    Find the complementary function.
    [3 marks]
    (b)
    Find the particular solution for which y=1y=1 and dydx=0\frac{dy}{dx}=0 when x=0x=0.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A mass on a spring is driven by an external force, so that its displacement xx metres from equilibrium at time tt seconds satisfies d2xdt2+2dxdt+5x=17cos⁡2t\frac{d^2x}{dt^2}+2\frac{dx}{dt}+5x=17\cos2t.
    (a)
    Find the general solution of the differential equation.
    [6 marks]
    (b)
    (i) Given that x=1x=1 and dxdt=0\frac{dx}{dt}=0 when t=0t=0, find xx in terms of tt. [4]
    (ii) Describe the long-term motion of the mass and state its amplitude. [2]
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    The concentration CC mg per litre of a drug in a patient's blood at time tt hours after an injection satisfies dCdt+0.4C=6e−0.1t\frac{dC}{dt}+0.4C=6\mathrm{e}^{-0.1t}.
    (a)
    Find the integrating factor.
    [1 mark]
    • Ae−0.4t\mathrm{e}^{-0.4t}
    • B0.4t0.4t
    • Ce0.4t\mathrm{e}^{0.4t}
    • De0.4\mathrm{e}^{0.4}
    (b)
    After multiplying the equation by the integrating factor, what is the right-hand side?
    [1 mark]
    • A6e−0.5t6\mathrm{e}^{-0.5t}
    • B6e0.5t6\mathrm{e}^{0.5t}
    • C6e−0.1t6\mathrm{e}^{-0.1t}
    • D6e0.3t6\mathrm{e}^{0.3t}
    (c)
    Given that C=0C=0 when t=0t=0, show that C=20(e−0.1t−e−0.4t)C=20\left(\mathrm{e}^{-0.1t}-\mathrm{e}^{-0.4t}\right).
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    A vehicle's suspension is modelled so that the vertical displacement xx metres of the body from equilibrium at time tt seconds satisfies d2xdt2+10dxdt+16x=0\frac{d^2x}{dt^2}+10\frac{dx}{dt}+16x=0.
    (a)
    Which statement describes the damping?
    [1 mark]
    • AHeavy damping, because the auxiliary equation has two distinct real roots
    • BCritical damping, because the auxiliary equation has a repeated root
    • CLight damping, because the auxiliary equation has complex roots
    • DNo damping, because the equation is homogeneous
    (b)
    Which expression is the general solution?
    [1 mark]
    • Ax=Ae2t+Be8tx=A\mathrm{e}^{2t}+B\mathrm{e}^{8t}
    • Bx=Ae−2t+Be−8tx=A\mathrm{e}^{-2t}+B\mathrm{e}^{-8t}
    • Cx=(A+Bt)e−2tx=(A+Bt)\mathrm{e}^{-2t}
    • Dx=e−5t(Acos⁡3t+Bsin⁡3t)x=\mathrm{e}^{-5t}(A\cos3t+B\sin3t)
    (c)
    Given that x=0.5x=0.5 and dxdt=0\frac{dx}{dt}=0 when t=0t=0, find xx in terms of tt.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    The temperature deviations xx and yy (in ∘^\circC) of two connected rooms from their target temperature at time tt hours satisfy dxdt=x−2y\frac{dx}{dt}=x-2y and dydt=3x−4y\frac{dy}{dt}=3x-4y.
    (a)
    Show that d2xdt2+3dxdt+2x=0\frac{d^2x}{dt^2}+3\frac{dx}{dt}+2x=0.
    [3 marks]
    (b)
    Given that x=3x=3 and y=2y=2 when t=0t=0, find xx and yy in terms of tt.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A model for a damped system has xx and yy satisfying dxdt=y\frac{dx}{dt}=y and dydt=−9x−6y\frac{dy}{dt}=-9x-6y for t≥0t\ge0, with x=2x=2 and y=4y=4 when t=0t=0.
    (a)
    Show that d2xdt2+6dxdt+9x=0\frac{d^2x}{dt^2}+6\frac{dx}{dt}+9x=0, and hence find xx and yy in terms of tt.
    [6 marks]
    (b)
    The model describes the displacement xx of a damped oscillator.
    (i) Explain why the system is critically damped. [2]

    (ii) Find the maximum value of
    xx for t≥0t\ge0, and the time at which it occurs. [4]
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).