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Further Mechanics 2: Further kinematicsEdexcel A-Level Further Maths: Topic test

20 questions, 54 marks

Edexcel A-Level Further Maths

Further Mechanics 2: Further kinematics topic test

Total 54 marks

Name

Class

Date

  1. 1
    A cyclist starts from rest at time t=0t=0 and moves along a straight track. For 0≤t≤50\le t\le5, where tt is in seconds, the acceleration of the cyclist is (2−0.4t)(2-0.4t) m s⁻².
    (a)
    What is the speed of the cyclist when t=5t=5?
    [1 mark]
    • A1010 m s⁻¹
    • B55 m s⁻¹
    • C22 m s⁻¹
    • D00 m s⁻¹
    (b)
    What is the distance travelled by the cyclist in the first 5 seconds?
    [1 mark]
    • A2525 m
    • B12.512.5 m
    • C8.338.33 m
    • D16.716.7 m
    (c)
    Find the time at which the speed of the cyclist is 4.2 m s⁻¹.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A cart moves along a straight horizontal track. At time tt seconds its speed is vv m s⁻¹, and magnetic braking gives it a deceleration of 0.4v0.4v m s⁻². The initial speed of the cart is 10 m s⁻¹.
    (a)
    Which expression gives vv at time tt?
    [1 mark]
    • A10e−0.4t10\mathrm e^{-0.4t}
    • B10−0.4t10-0.4t
    • C10e0.4t10\mathrm e^{0.4t}
    • D4e−10t4\mathrm e^{-10t}
    (b)
    After how many seconds is the speed of the cart 5 m s⁻¹?
    [1 mark]
    • A12.512.5 s
    • B0.2770.277 s
    • C1.731.73 s
    • D2.52.5 s
    (c)
    Find the distance travelled by the cart in the first 2 seconds.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A particle PP moves along the xx-axis. At time t=0t=0, PP is at the origin OO and has velocity 4 m s⁻¹ in the positive xx-direction. At time tt seconds, the acceleration of PP is 6e−2t6\mathrm e^{-2t} m s⁻².
    (a)
    Show that the velocity of PP at time tt is (7−3e−2t)\left(7-3\mathrm e^{-2t}\right) m s⁻¹.
    [3 marks]
    (b)
    Find the distance of PP from OO when t=ln⁡2t=\ln2.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A drone is launched from rest at ground level and rises vertically. At time tt seconds, where t≥0t\ge0, its upward acceleration is 6(1−t2)e−t2/26\left(1-t^2\right)\mathrm e^{-t^2/2} m s⁻².
    (a)
    Show that ddt(te−t2/2)=(1−t2)e−t2/2\frac{\mathrm d}{\mathrm dt}\left(t\mathrm e^{-t^2/2}\right)=\left(1-t^2\right)\mathrm e^{-t^2/2}. Hence find the velocity of the drone at time tt, and its greatest speed.
    [6 marks]
    (b)
    Find the height of the drone above the ground at time tt. Hence find the time at which the drone is 3 m above the ground.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    A particle PP moves in a straight line. At time t=0t=0 its speed is 4 m s⁻¹, and while it is moving in the positive direction its deceleration has magnitude v2v^2 m s⁻², where vv m s⁻¹ is its speed at time tt seconds.
    (a)
    Which expression gives vv at time tt?
    [1 mark]
    • A4e−t4\mathrm e^{-t}
    • B41+t\frac{4}{1+t}
    • C4−16t4-16t
    • D41+4t\frac{4}{1+4t}
    (b)
    At what time is the speed of PP equal to 0.5 m s⁻¹?
    [1 mark]
    • A77 s
    • B1.751.75 s
    • C0.43750.4375 s
    • D22 s
    (c)
    Find the distance travelled by PP in the first second.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    A lift moves vertically for 4 seconds. At time tt seconds, where 0≤t≤40\le t\le4, its upward velocity is 2sin⁡(πt4)2\sin\left(\frac{\pi t}{4}\right) m s⁻¹.
    (a)
    What is the acceleration of the lift when t=0t=0?
    [1 mark]
    • Aπ4\frac{\pi}{4} m s⁻²
    • B22 m s⁻²
    • Cπ2\frac{\pi}{2} m s⁻²
    • D8π\frac{8}{\pi} m s⁻²
    (b)
    What is the distance travelled by the lift in the 4 seconds?
    [1 mark]
    • A16π\frac{16}{\pi} m
    • B8π\frac{8}{\pi} m
    • C88 m
    • D44 m
    (c)
    Find the value of tt, with 0<t≤40<t\le4, at which the acceleration of the lift is zero.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    A particle PP starts from rest at time t=0t=0 and moves in a straight line. At time tt seconds, where t≥0t\ge0, the acceleration of PP is 12(1+t)2\frac{12}{(1+t)^2} m s⁻² in the direction of motion.
    (a)
    Show that the speed of PP at time tt is 12t1+t\frac{12t}{1+t} m s⁻¹.
    [3 marks]
    (b)
    Find the distance travelled by PP in the first 5 seconds.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A particle PP moves along the positive xx-axis. At time t=0t=0, PP is at the origin OO with speed 2 m s⁻¹. At time tt seconds, the acceleration of PP is 3v\frac3v m s⁻², where vv m s⁻¹ is the speed of PP and v>0v>0.
    (a)
    Show that v=6t+4v=\sqrt{6t+4}.
    [6 marks]
    (b)
    Find the distance of PP from OO when t=10t=10, and the acceleration of PP at that time.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).