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Decision Mathematics 1: Algorithms on graphs IIEdexcel A-Level Further Maths: Topic test

20 questions, 54 marks

Edexcel A-Level Further Maths

Decision Mathematics 1: Algorithms on graphs II topic test

Total 54 marks

Name

Class

Date

  1. 1
    A road network has five junctions PP, QQ, RR, SS and TT. The road lengths in km are PQ=6PQ=6, PR=4PR=4, QR=5QR=5, QS=7QS=7, RS=3RS=3, RT=8RT=8 and ST=5ST=5. An inspector must travel along every road and return to the start.
    (a)
    Which vertices have odd degree?
    [1 mark]
    • APP and TT
    • BQQ and SS
    • CRR and SS
    • DQQ and RR
    (b)
    What is the length of the shortest route that travels along every road and returns to its starting vertex?
    [1 mark]
    • A3838 km
    • B4646 km
    • C5252 km
    • D4545 km
    (c)
    The road RTRT is closed. Find the length of the shortest route along every remaining road that returns to its start.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A network of paths has a total length of 62 km. Exactly four vertices, AA, BB, CC and DD, have odd degree. The shortest distances between them, in km, are AB=7AB=7, AC=11AC=11, AD=5AD=5, BC=6BC=6, BD=9BD=9 and CD=8CD=8.
    (a)
    How many different ways are there of pairing up the four odd vertices?
    [1 mark]
    • A33
    • B22
    • C44
    • D66
    (b)
    Which pairing of the odd vertices gives the shortest repeated distance?
    [1 mark]
    • AABAB and CDCD
    • BACAC and BDBD
    • CADAD and BCBC
    • DABAB and ADAD
    (c)
    Find the length of the shortest route that travels along every path and returns to its starting vertex.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A salesman must visit five towns AA, BB, CC, DD and EE, each once, and return to the start. The network of distances in km between the towns is complete and satisfies the triangle inequality: AB=12AB=12, AC=9AC=9, AD=15AD=15, AE=11AE=11, BC=10BC=10, BD=14BD=14, BE=8BE=8, CD=13CD=13, CE=7CE=7 and DE=6DE=6.
    (a)
    Use the nearest neighbour algorithm, starting at AA, to find an upper bound for the length of the optimal tour.
    [3 marks]
    (b)
    By deleting vertex DD, find a lower bound for the length of the optimal tour.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A courier operates between five depots AA, BB, CC, DD and EE joined by roads with lengths in km: AB=8AB=8, AC=5AC=5, AE=11AE=11, BC=6BC=6, BD=9BD=9, CD=7CD=7, CE=10CE=10 and DE=4DE=4.
    (a)
    An inspector must travel along every road and return to the starting depot. Find the length of the shortest route.
    [6 marks]
    (b)
    A different driver must visit every depot exactly once and return to the start, so the roads are first converted into a complete network of shortest distances. Show that AD=12AD=12 and BE=13BE=13 in this network. Then use the nearest neighbour algorithm from AA to find an upper bound, and delete EE to find a lower bound, for the optimal tour.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    A connected network has six vertices with degrees 22, 33, 33, 44, 44 and 44. The total length of all its roads is 52 km. The two vertices of odd degree are XX and YY, and the shortest distance between XX and YY is 9 km.
    (a)
    Which statement about the network is correct?
    [1 mark]
    • AIt has a closed route that uses every road exactly once
    • BEvery route that uses every road must repeat at least three roads
    • CIt has a trail that uses every road exactly once, but no such closed route
    • DNo route can use every road exactly once
    (b)
    What is the length of the shortest route that travels along every road and returns to its start?
    [1 mark]
    • A6161 km
    • B5252 km
    • C7070 km
    • D4343 km
    (c)
    Find the length of the shortest route that travels along every road and finishes at a different vertex from where it starts, and say where it should start and finish.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    In a classical travelling salesman problem on a complete network of five vertices that satisfies the triangle inequality, the vertex VV is deleted. The minimum spanning tree of the other four vertices has weight 24, and the two shortest edges at VV have lengths 5 and 8. Doubling the edges of a minimum spanning tree of the whole network gives a closed walk of length 52 that visits every vertex.
    (a)
    What lower bound for the optimal tour does the deleted vertex method give?
    [1 mark]
    • A2424
    • B2929
    • C1313
    • D3737
    (b)
    Which statement about the length TT of the optimal tour must be true?
    [1 mark]
    • AT≤37T\le37
    • B37≤T≤5237\le T\le52
    • CT≥52T\ge52
    • DT=45T=45
    (c)
    In the closed walk of length 52, vertex YY is visited a second time on a section X→Y→ZX\to Y\to Z whose edges have lengths 10 and 14. The direct edge XZXZ has length 19. Find the improved upper bound after using this shortcut.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    A village has six junctions GG, HH, JJ, KK, LL and MM joined by roads whose lengths in km are GH=5GH=5, GJ=7GJ=7, HJ=4HJ=4, HK=8HK=8, JL=6JL=6, KL=3KL=3, KM=9KM=9 and LM=5LM=5. A road inspector must travel along every road and return to the starting junction.
    (a)
    Identify the vertices of odd degree and find the total length that must be repeated for each possible pairing of them.
    [3 marks]
    (b)
    Find the length of the shortest route, and state which roads are travelled twice.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A nature reserve has five junctions PP, QQ, RR, SS and TT joined by paths whose lengths in km are PQ=7PQ=7, PR=9PR=9, PT=11PT=11, QR=5QR=5, QS=8QS=8, RS=6RS=6, RT=10RT=10 and ST=4ST=4.
    (a)
    A warden must walk along every path and return to the starting junction. Find the length of the shortest route.
    [6 marks]
    (b)
    A guide must instead visit every junction exactly once and return to the start. The shortest distances between junctions, in km, are PQ=7PQ=7, PR=9PR=9, PS=15PS=15, PT=11PT=11, QR=5QR=5, QS=8QS=8, QT=12QT=12, RS=6RS=6, RT=10RT=10 and ST=4ST=4. Use a minimum spanning tree to find an upper bound for the optimal tour, then use shortcuts to improve it.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).