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Further Statistics 1: Poisson and binomial distributionsEdexcel A-Level Further Maths: Topic test

20 questions, 54 marks

Edexcel A-Level Further Maths

Further Statistics 1: Poisson and binomial distributions topic test

Total 54 marks

Name

Class

Date

  1. 1
    Potholes along a country road occur randomly and independently, at a mean rate of 1.51.5 per kilometre.
    (a)
    Which distribution models the number of potholes in a 22 km stretch of the road?
    [1 mark]
    • APo(1.5)\mathrm{Po}(1.5)
    • BPo(3)\mathrm{Po}(3)
    • CPo(0.75)\mathrm{Po}(0.75)
    • DPo(3.5)\mathrm{Po}(3.5)
    (b)
    Let XX be the number of potholes in a 22 km stretch. What is P(X=2)P(X=2)?
    [1 mark]
    • A0.25100.2510
    • B0.42320.4232
    • C0.04980.0498
    • D0.22400.2240
    (c)
    Find the probability that a randomly chosen 11 km stretch contains at least one pothole.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Kingfishers and herons are seen on a stretch of river at random and independently. The number of kingfishers seen per hour has a Poisson distribution with mean 0.60.6, and the number of herons seen per hour has a Poisson distribution with mean 1.41.4.
    (a)
    Which distribution models the total number of these birds seen in one hour?
    [1 mark]
    • APo(2.0)\mathrm{Po}(2.0)
    • BPo(0.84)\mathrm{Po}(0.84)
    • CPo(1.0)\mathrm{Po}(1.0)
    • DPo(0.8)\mathrm{Po}(0.8)
    (b)
    What is the probability that, in a three-hour period, at most one bird in total is seen?
    [1 mark]
    • A0.00250.0025
    • B0.01490.0149
    • C0.01740.0174
    • D0.06200.0620
    (c)
    Find the probability that exactly one kingfisher is seen in a two-hour period.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The random variable Y∼B(n,p)Y\sim\mathrm{B}(n,p) has mean 4.54.5 and variance 3.153.15.
    (a)
    Find the values of nn and pp.
    [3 marks]
    (b)
    Find P(3≤Y≤6)P(3\le Y\le6).
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A seed supplier sells packets of 250250 seeds. Each seed independently fails to germinate with probability 0.0080.008. Let XX be the number of seeds in a packet that fail to germinate.
    (a)
    (i) Give two reasons why a Poisson distribution is suitable to approximate the distribution of XX.
    (ii) Use a Poisson approximation to find
    P(X=2)P(X=2).
    (iii) Find
    P(X=2)P(X=2) using the binomial distribution and comment on your two answers.
    [6 marks]
    (b)
    A customer buys three packets. Using the Poisson approximation for each packet, let TT be the total number of seeds in the three packets that fail to germinate.
    (i) State the distribution of
    TT.
    (ii) Find
    P(T≥8)P(T\ge8).
    (iii) The customer buys three packets on each of two days. Assuming independence, find the probability that
    T≥8T\ge8 on exactly one of the two days.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    Meteors are observed at random, independently of one another, at a mean rate of 3.63.6 per hour.
    (a)
    Which of these is an assumption needed to model the number of meteors in a fixed time with a Poisson distribution?
    [1 mark]
    • AMeteors occur at regular intervals.
    • BThe mean rate changes through the night.
    • CMeteors occur independently of one another.
    • DNo more than 33 meteors can occur in any hour.
    (b)
    What is the probability that at least 22 meteors are observed in a 3030 minute period?
    [1 mark]
    • A0.5370.537
    • B0.4630.463
    • C0.2970.297
    • D0.8740.874
    (c)
    Find the probability that more than 33 meteors are observed in a one hour period.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    The random variable X∼B(40,0.35)X\sim\mathrm{B}(40,0.35).
    (a)
    What is Var(X)\mathrm{Var}(X)?
    [1 mark]
    • A1414
    • B0.22750.2275
    • C2626
    • D9.19.1
    (b)
    A student suggests approximating XX by Po(14)\mathrm{Po}(14). Which statement is the best reason why this is unsuitable?
    [1 mark]
    • Ann is too large for a Poisson approximation.
    • Bpp is not small, and the variance of XX is 9.19.1 whereas a Poisson variable with mean 1414 has variance 1414.
    • CThe mean of XX is not 1414.
    • DThe probability of success must be exactly 0.50.5.
    (c)
    Find P(X=12)P(X=12).
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    The number of scratches, XX, on a metal panel has a Poisson distribution with mean λ\lambda. Exactly 20%20\% of panels have no scratches.
    (a)
    Find the value of λ\lambda.
    [3 marks]
    (b)
    (i) Find the probability that a panel has at least 33 scratches.
    (ii) A sample of
    150150 panels has a mean of 1.581.58 scratches and a variance of 2.92.9. Comment on the suitability of the Poisson model.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    Sachets of seed are packed in boxes of 150150. Each sachet is independently underweight with probability 0.020.02. Let XX be the number of underweight sachets in a box.
    (a)
    (i) Find E(X)\mathrm{E}(X) and Var(X)\mathrm{Var}(X).
    (ii) Use a Poisson approximation to find the probability that a box has at least
    55 underweight sachets.
    (iii) A pallet holds
    1212 boxes. Using your answer to part (ii), find the probability that exactly 22 boxes on the pallet have at least 55 underweight sachets.
    [6 marks]
    (b)
    A second machine QQ packs boxes in which the number of underweight sachets has a Poisson distribution with mean 1.51.5, independent of machine PP. A retailer opens one box packed by the first machine, with XX approximated by Po(3)\mathrm{Po}(3), and one box packed by QQ. Let UU be the total number of underweight sachets in the two boxes.
    (i) Explain why
    U∼Po(4.5)U\sim\mathrm{Po}(4.5).
    (ii) Find
    P(U=4)P(U=4).
    (iii) Find
    P(U≥8)P(U\ge8).
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).