Decision Mathematics 1: Critical path analysisEdexcel A-Level Further Maths: Topic test
20 questions, 54 marks
Edexcel A-Level Further Maths
Decision Mathematics 1: Critical path analysis topic test
Total 54 marks
Name
Class
Date
- 1A project is modelled by an activity network drawn with activities on arcs. The events are numbered 1 to 6. The activities are (event 1 to 2), (1 to 3), (2 to 5), (3 to 4), (5 to 6) and (4 to 6). There is also a dummy activity from event 2 to event 3 and another dummy from event 4 to event 5.(a)What are the immediate predecessors of activity ?[1 mark]
- A only
- B and
- C only
- D, and
(b)Which activity can start as soon as has finished, without waiting for any other activity to finish?[1 mark]- A
- B and
- CNeither, because of the dummy
- D
(c)Complete the precedence table by giving the immediate predecessors of each of the activities to .[2 marks]Total for question 1: 4 marks
- 2A project has seven activities. Each activity, its duration in days and its immediate predecessors are: 4 (none); 6 (none); 3 (); 5 (, ); 7 (); 4 (); 5 (, ).(a)What is the minimum time in which the project can be completed?[1 mark]
- A days
- B days
- C days
- D days
(b)Which activities are on the critical path?[1 mark]- A, , ,
- B, , ,
- C, , ,
- D, , ,
(c)Find the total float of activity .[2 marks]Total for question 2: 4 marks
- 3A project has six activities. Each activity, its duration in days, the number of workers it needs and its immediate predecessors are: 2 days, 3 workers (none); 4 days, 2 workers (none); 3 days, 1 worker (none); 4 days, 1 worker (); 4 days, 3 workers (); 3 days, 2 workers (). The minimum completion time of the project is 10 days, and the critical activities are , and .(a)Every activity starts at its earliest possible time. Find the number of workers needed on each of the ten days.[3 marks](b)Only 4 workers are available at any time. Show that the project can still be completed in 10 days by delaying one activity, and give the start time of every activity.[4 marks]
Total for question 3: 7 marks
- 4A project has seven activities, each needing one worker. Each activity, its duration in days and its immediate predecessors are: 4 (none); 4 (none); 6 (); 6 (); 3 (, , ); 5 (none); 2 ().(a)Carry out a forward pass and a backward pass to find the earliest and latest start times of every activity, the minimum completion time, the critical activities and the total float of and of .[6 marks](b)Find a lower bound for the number of workers needed to complete the project in the minimum time, and construct a schedule, stating which activities each worker does and when, that achieves this.[6 marks]
Total for question 4: 12 marks
- 5A project has four activities, , , and . Their immediate predecessors are: none; none; is preceded by and ; is preceded by only. The project is to be modelled by an activity network with activities on arcs.(a)What is the least number of dummy activities needed in the network?[1 mark]
- A
- B
- C
- D
(b)Which statement describes the dummy activity?[1 mark]- AIt runs from the end of to the start of , so that follows both and while follows only
- BIt runs from the end of to the start of , so that follows
- CIt runs from the end of to the start of , so that follows
- DIt runs from the end of to the start of , so that follows
(c)Two more activities are added: is preceded by and , and is preceded by only. State, with a reason, how many further dummy activities are needed.[2 marks]Total for question 5: 4 marks
- 6In a project each activity needs one worker. The sum of all the activity durations is 70 days and the minimum project time is 30 days. Activity lasts 6 days. Its start event has earliest event time 5 and its finish event has latest event time 17.(a)What is the total float of activity ?[1 mark]
- A days
- B days
- C days
- D days
(b)Activity is delayed by 4 days. What is the effect on the minimum project time?[1 mark]- AIt increases by 4 days
- BThere is no effect
- CIt increases by 2 days
- DIt increases by 6 days
(c)Find a lower bound for the number of workers needed to complete the project in 30 days.[2 marks]Total for question 6: 4 marks
- 7A project has six activities. Each activity, its duration in days, the number of workers it needs and its immediate predecessors are: 5 days, 2 workers (none); 2 days, 1 worker (none); 5 days, 1 worker (none); 5 days, 1 worker (); 2 days, 3 workers (); 3 days, 2 workers (, , ). The minimum completion time is 10 days and the critical activities are , and .(a)Every activity starts at its earliest possible time. Find the number of workers needed on each of the ten days.[3 marks](b)Only 4 workers are available at any time. Show that the project can still be completed in 10 days by delaying one activity, and give the start time of every activity.[4 marks]
Total for question 7: 7 marks
- 8A project has seven activities, each needing one worker. Each activity, its duration in days and its immediate predecessors are: 7 (none); 2 (none); 7 (); 5 (none); 2 (); 4 (, ); 5 ().(a)Carry out a forward pass and a backward pass to find the minimum completion time, the critical activities and the total float of , and .[6 marks](b)Find a lower bound for the number of workers needed to complete the project in the minimum time, and construct a schedule, stating which activities each worker does and when, that achieves this.[6 marks]
Total for question 8: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).