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Further Pure 2: Further matrix algebraEdexcel A-Level Further Maths: Topic test

20 questions, 54 marks

Edexcel A-Level Further Maths

Further Pure 2: Further matrix algebra topic test

Total 54 marks

Name

Class

Date

  1. 1
    The matrix M=(1243)\mathbf{M}=\begin{pmatrix}1&2\\ 4&3\end{pmatrix} has real eigenvalues.
    (a)
    What is the characteristic equation of M\mathbf{M}?
    [1 mark]
    • Aλ2−4λ−5=0\lambda^2-4\lambda-5=0
    • Bλ2+4λ−5=0\lambda^2+4\lambda-5=0
    • Cλ2−4λ+5=0\lambda^2-4\lambda+5=0
    • Dλ2−4λ+11=0\lambda^2-4\lambda+11=0
    (b)
    Which vector is an eigenvector of M\mathbf{M} corresponding to the eigenvalue 55?
    [1 mark]
    • A(1−2)\begin{pmatrix}1\\ -2\end{pmatrix}
    • B(21)\begin{pmatrix}2\\ 1\end{pmatrix}
    • C(12)\begin{pmatrix}1\\ 2\end{pmatrix}
    • D(1−1)\begin{pmatrix}1\\ -1\end{pmatrix}
    (c)
    Find an eigenvector of M\mathbf{M} corresponding to the eigenvalue −1-1.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The matrix N=(2−136)\mathbf{N}=\begin{pmatrix}2&-1\\ 3&6\end{pmatrix}.
    (a)
    What is the characteristic equation of N\mathbf{N}?
    [1 mark]
    • Aλ2+8λ+15=0\lambda^2+8\lambda+15=0
    • Bλ2−8λ+15=0\lambda^2-8\lambda+15=0
    • Cλ2−8λ+9=0\lambda^2-8\lambda+9=0
    • Dλ2−8λ−15=0\lambda^2-8\lambda-15=0
    (b)
    By the Cayley-Hamilton theorem, which expression is equal to N3\mathbf{N}^3?
    [1 mark]
    • A8N−15I8\mathbf{N}-15\mathbf{I}
    • B64N−120I64\mathbf{N}-120\mathbf{I}
    • C49N−15I49\mathbf{N}-15\mathbf{I}
    • D49N−120I49\mathbf{N}-120\mathbf{I}
    (c)
    Use the Cayley-Hamilton theorem to find N−1\mathbf{N}^{-1}.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The matrix B=(3−51−1)\mathbf{B}=\begin{pmatrix}3&-5\\ 1&-1\end{pmatrix} has complex eigenvalues.
    (a)
    Find the eigenvalues of B\mathbf{B}.
    [3 marks]
    (b)
    Find an eigenvector of B\mathbf{B} corresponding to each eigenvalue.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The symmetric matrix S=(200031013)\mathbf{S}=\begin{pmatrix}2&0&0\\ 0&3&1\\ 0&1&3\end{pmatrix}.
    (a)
    Show that S\mathbf{S} has a repeated eigenvalue, and find the eigenvalues and corresponding eigenvectors.
    [6 marks]
    (b)
    Find an orthogonal matrix P\mathbf{P} and a diagonal matrix D\mathbf{D} such that PTSP=D\mathbf{P}^{\mathrm{T}}\mathbf{S}\mathbf{P}=\mathbf{D}, and hence find S4\mathbf{S}^4.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    The matrix A=(5−24−1)\mathbf{A}=\begin{pmatrix}5&-2\\ 4&-1\end{pmatrix} has eigenvector (12)\begin{pmatrix}1\\ 2\end{pmatrix} with eigenvalue 11 and eigenvector (11)\begin{pmatrix}1\\ 1\end{pmatrix} with eigenvalue 33. The matrix P\mathbf{P} has these two eigenvectors as its columns, in the order given, so that P−1AP=D\mathbf{P}^{-1}\mathbf{A}\mathbf{P}=\mathbf{D} for a diagonal matrix D\mathbf{D}.
    (a)
    What is D\mathbf{D}?
    [1 mark]
    • Adiag⁡(3,1)\operatorname{diag}(3,1)
    • Bdiag⁡(1,3)\operatorname{diag}(1,3)
    • Cdiag⁡(1,2)\operatorname{diag}(1,2)
    • Ddiag⁡(5,−1)\operatorname{diag}(5,-1)
    (b)
    What are the eigenvalues of A4\mathbf{A}^4?
    [1 mark]
    • A11 and 8181
    • B44 and 1212
    • C11 and 1212
    • D11 and 99
    (c)
    Write down P−1\mathbf{P}^{-1}.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    The matrix K=(4−112)\mathbf{K}=\begin{pmatrix}4&-1\\ 1&2\end{pmatrix}.
    (a)
    What is the repeated eigenvalue of K\mathbf{K}?
    [1 mark]
    • A11
    • B22
    • C66
    • D33
    (b)
    Which vector is an eigenvector of K\mathbf{K}?
    [1 mark]
    • A(1−1)\begin{pmatrix}1\\ -1\end{pmatrix}
    • B(13)\begin{pmatrix}1\\ 3\end{pmatrix}
    • C(11)\begin{pmatrix}1\\ 1\end{pmatrix}
    • D(4−1)\begin{pmatrix}4\\ -1\end{pmatrix}
    (c)
    Explain why K\mathbf{K} cannot be diagonalised.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    The matrix T=(110021003)\mathbf{T}=\begin{pmatrix}1&1&0\\ 0&2&1\\ 0&0&3\end{pmatrix}.
    (a)
    Show that the characteristic equation of T\mathbf{T} is λ3−6λ2+11λ−6=0\lambda^3-6\lambda^2+11\lambda-6=0.
    [3 marks]
    (b)
    Use the Cayley-Hamilton theorem to find T−1\mathbf{T}^{-1}.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    The matrix M=(01−23)\mathbf{M}=\begin{pmatrix}0&1\\ -2&3\end{pmatrix}.
    (a)
    Find the eigenvalues of M\mathbf{M} and a normalised eigenvector for each.
    [6 marks]
    (b)
    Find Mn\mathbf{M}^n in terms of nn, and verify your result for n=2n=2 using the Cayley-Hamilton theorem.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).