All worksheets topics

5.11 Further integrationIB Maths: Applications and Interpretation HL: Subtopic test

10 questions, 27 marks

IB Maths: Applications and Interpretation HL

5.11 Further integration

Total 27 marks

Name

Class

Date

  1. 1
    Water flows into a tank at a rate of r(t)=6tr(t)=6\sqrt{t} litres per minute, where tt is the time in minutes since the flow started. The tank is empty when t=0t=0.
    (a)
    Find ∫6t dt\displaystyle\int6\sqrt{t}\,dt.
    [1 mark]
    • A3t−1/2+c3t^{-1/2}+c
    • B6t3/2+c6t^{3/2}+c
    • C9t3/2+c9t^{3/2}+c
    • D4t3/2+c4t^{3/2}+c
    (b)
    Find the volume of water that flows into the tank between t=1t=1 and t=4t=4.
    [1 mark]
    • A1818 litres
    • B2828 litres
    • C3232 litres
    • D44 litres
    (c)
    Find the time taken for the volume of water in the tank to reach 500500 litres.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The population of a colony of bacteria changes at a rate dPdt=123t+2\dfrac{dP}{dt}=\dfrac{12}{3t+2} thousand per hour, where tt is the time in hours and t≥0t\ge0. At t=0t=0 the population is 55 thousand.
    (a)
    Find ∫123t+2 dt\displaystyle\int\frac{12}{3t+2}\,dt.
    [1 mark]
    • A4ln⁡(3t+2)+c4\ln(3t+2)+c
    • B12ln⁡(3t+2)+c12\ln(3t+2)+c
    • C−4(3t+2)2+c-\dfrac{4}{(3t+2)^2}+c
    • D36ln⁡(3t+2)+c36\ln(3t+2)+c
    (b)
    Find the increase in the population between t=0t=0 and t=6t=6.
    [1 mark]
    • A4ln⁡18≈11.64\ln18\approx11.6 thousand
    • B12ln⁡10≈27.612\ln10\approx27.6 thousand
    • C4ln⁡10≈9.214\ln10\approx9.21 thousand
    • D4ln⁡20≈12.04\ln20\approx12.0 thousand
    (c)
    Find the time at which the population reaches 2020 thousand.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A particle moves in a straight line. At time tt seconds its velocity is v=4tsin⁡(t2)v=4t\sin(t^2) m s−1^{-1}, where the angle is in radians. The displacement ss from the starting point is 00 when t=0t=0.
    (a)
    Find an expression for ss in terms of tt.
    [3 marks]
    (b)
    Find the first time after t=0t=0 at which the particle is at rest, and its displacement from the starting point at that time.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A curve y=f(x)y=f(x), defined for 0≤x<π20\le x<\dfrac{\pi}{2}, passes through the point (0, 4)(0,\,4). Its gradient function is f′(x)=sin⁡xcos⁡x+2cos⁡2xf'(x)=\dfrac{\sin x}{\cos x}+\dfrac{2}{\cos^2x}.
    (a)
    (i) Use the substitution u=cos⁡xu=\cos x to show that ∫sin⁡xcos⁡x dx=−ln⁡(cos⁡x)+c\displaystyle\int\frac{\sin x}{\cos x}\,dx=-\ln(\cos x)+c.
    (ii) Hence find
    f(x)f(x).
    [6 marks]
    (b)
    (i) Find the exact value of ∫0π/4f′(x) dx\displaystyle\int_0^{\pi/4}f'(x)\,dx, giving your answer in the form a+bln⁡2a+b\ln2.
    (ii) Hence find the exact value of
    f(π4)f\left(\frac{\pi}{4}\right).
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).