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5.18 Second order differential equationsIB Maths: Applications and Interpretation HL: Subtopic test

10 questions, 27 marks

IB Maths: Applications and Interpretation HL

5.18 Second order differential equations

Total 27 marks

Name

Class

Date

  1. 1
    The displacement xx metres of a mass on a spring, tt seconds after release, satisfies d2xdt2=−x\frac{d^2x}{dt^2}=-x, with x=1x=1 and dxdt=0\frac{dx}{dt}=0 when t=0t=0. Euler's method with step length h=0.1h=0.1 seconds is used, with y=dxdty=\frac{dx}{dt}.
    (a)
    Using y=dxdty=\frac{dx}{dt}, which pair of first-order equations is equivalent to d2xdt2=−x\frac{d^2x}{dt^2}=-x?
    [1 mark]
    • Adxdt=y\frac{dx}{dt}=y and dydt=−x\frac{dy}{dt}=-x
    • Bdxdt=−x\frac{dx}{dt}=-x and dydt=y\frac{dy}{dt}=y
    • Cdxdt=y\frac{dx}{dt}=y and dydt=x\frac{dy}{dt}=x
    • Ddxdt=−y\frac{dx}{dt}=-y and dydt=x\frac{dy}{dt}=x
    (b)
    Find the values of xx and yy when t=0.1t=0.1.
    [1 mark]
    • Ax=0.9x=0.9, y=0y=0
    • Bx=1x=1, y=0.1y=0.1
    • Cx=1x=1, y=−0.1y=-0.1
    • Dx=0.9x=0.9, y=−0.1y=-0.1
    (c)
    Find the approximation to xx when t=0.2t=0.2.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The displacement xx cm of a damped oscillator, tt seconds after it starts, satisfies d2xdt2+2dxdt+10x=0\frac{d^2x}{dt^2}+2\frac{dx}{dt}+10x=0. Let y=dxdty=\frac{dx}{dt}.
    (a)
    Which pair of first-order equations is equivalent to the second-order equation?
    [1 mark]
    • Adxdt=y\frac{dx}{dt}=y and dydt=10x+2y\frac{dy}{dt}=10x+2y
    • Bdxdt=y\frac{dx}{dt}=y and dydt=−10x+2y\frac{dy}{dt}=-10x+2y
    • Cdxdt=−2y\frac{dx}{dt}=-2y and dydt=−10x\frac{dy}{dt}=-10x
    • Ddxdt=y\frac{dx}{dt}=y and dydt=−10x−2y\frac{dy}{dt}=-10x-2y
    (b)
    Find the eigenvalues of the matrix that represents the coupled system.
    [1 mark]
    • A1±3i1\pm3i
    • B−1±3i-1\pm3i
    • C−2±10i-2\pm10i
    • D−1±i10-1\pm i\sqrt{10}
    (c)
    Describe the motion of the oscillator, giving a reason.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A mass on a spring has displacement xx metres at time tt seconds, where d2xdt2=−4x−0.5dxdt\frac{d^2x}{dt^2}=-4x-0.5\frac{dx}{dt}, with x=2x=2 and dxdt=0\frac{dx}{dt}=0 when t=0t=0. Let y=dxdty=\frac{dx}{dt}. Euler's method with step length h=0.2h=0.2 seconds is used.
    (a)
    Write the second-order equation as a pair of coupled first-order equations, and write down the values of xx and yy when t=0t=0.
    [3 marks]
    (b)
    Use Euler's method to find xx and dxdt\frac{dx}{dt} when t=0.4t=0.4.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The angle θ\theta radians of a pendulum from the vertical, tt seconds after release, satisfies d2θdt2=−10sin⁡θ−0.5dθdt\frac{d^2\theta}{dt^2}=-10\sin\theta-0.5\frac{d\theta}{dt}, with θ=1\theta=1 and dθdt=0\frac{d\theta}{dt}=0 when t=0t=0. Let ω=dθdt\omega=\frac{d\theta}{dt}. Use radians on your GDC.
    (a)
    (i) Write the equation as a pair of coupled first-order equations.
    (ii) Use Euler's method with step length
    h=0.1h=0.1 to estimate θ\theta and ω\omega when t=0.2t=0.2, giving your answers to 3 significant figures.
    [6 marks]
    (b)
    For small angles, sin⁡θ≈θ\sin\theta\approx\theta.
    (i) Use this to write the equation as a coupled system
    ddt(θω)=M(θω)\frac{d}{dt}\begin{pmatrix} \theta \\ \omega \end{pmatrix}=M\begin{pmatrix} \theta \\ \omega \end{pmatrix}, and show that the eigenvalues of MM satisfy λ2+0.5λ+10=0\lambda^2+0.5\lambda+10=0.
    (ii) Find the eigenvalues of
    MM.
    (iii) Describe the long-term motion of the pendulum, giving a reason.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).