All worksheets topics

3.9 Matrix transformationsIB Maths: Applications and Interpretation HL: Subtopic test

10 questions, 27 marks

IB Maths: Applications and Interpretation HL

3.9 Matrix transformations

Total 27 marks

Name

Class

Date

  1. 1
    Transformation TT is represented by the matrix M=(0−110)\mathbf{M}=\begin{pmatrix}0 & -1 \\ 1 & 0\end{pmatrix}, so that a point (x,y)(x,y) maps to the point with position vector M(xy)\mathbf{M}\begin{pmatrix}x \\ y\end{pmatrix}.
    (a)
    Find the image of the point (3,2)(3,2) under TT.
    [1 mark]
    • A(2−3)\begin{pmatrix}2 \\ -3\end{pmatrix}
    • B(−3−2)\begin{pmatrix}-3 \\ -2\end{pmatrix}
    • C(−23)\begin{pmatrix}-2 \\ 3\end{pmatrix}
    • D(3−2)\begin{pmatrix}3 \\ -2\end{pmatrix}
    (b)
    Which of the following describes TT?
    [1 mark]
    • AA reflection in the line y=xy=x
    • BA rotation of 90∘90^\circ anticlockwise about the origin
    • CA rotation of 90∘90^\circ clockwise about the origin
    • DA reflection in the yy-axis
    (c)
    TT is followed by a reflection in the xx-axis, which has matrix R=(100−1)\mathbf{R}=\begin{pmatrix}1 & 0 \\ 0 & -1\end{pmatrix}. Find the single matrix that represents this combined transformation.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Triangle SS has area 88 cm2^2. It is transformed by the matrix N=(3122)\mathbf{N}=\begin{pmatrix}3 & 1 \\ 2 & 2\end{pmatrix} to give triangle S′S'.
    (a)
    Find the area of S′S'.
    [1 mark]
    • A3232 cm2^2
    • B1212 cm2^2
    • C22 cm2^2
    • D44 cm2^2
    (b)
    A second transformation has matrix (1003)\begin{pmatrix}1 & 0 \\ 0 & 3\end{pmatrix}. This transformation is
    [1 mark]
    • Aa horizontal stretch with scale factor 33
    • Ban enlargement with scale factor 33, centre the origin
    • Ca translation of 33 units in the positive yy direction
    • Da vertical stretch with scale factor 33
    (c)
    S′S' is then enlarged by scale factor 22, centre the origin, to give triangle S′′S''. Find the area of S′′S''.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A transformation UU maps a point with position vector (xy)\begin{pmatrix}x \\ y\end{pmatrix} to (2002)(xy)+(1−3)\begin{pmatrix}2 & 0 \\ 0 & 2\end{pmatrix}\begin{pmatrix}x \\ y\end{pmatrix}+\begin{pmatrix}1 \\ -3\end{pmatrix}. Triangle ABCABC has vertices A(1,2)A(1,2), B(4,2)B(4,2) and C(1,6)C(1,6), with lengths in cm.
    (a)
    Find the coordinates of the images A′A', B′B' and C′C' of the vertices of triangle ABCABC under UU.
    [3 marks]
    (b)
    (i) Find the area of triangle ABCABC.
    (ii) Write down the determinant of
    (2002)\begin{pmatrix}2 & 0 \\ 0 & 2\end{pmatrix}.
    (iii) Hence find the area of triangle
    A′B′C′A'B'C'.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A designer plots a spiral of points. The first point is P0=(8,0)P_0=(8,0) and each point, written as a column vector, is found from the previous one using Pn+1=RPnP_{n+1}=\mathbf{R}P_n, where R=(0−0.50.50)\mathbf{R}=\begin{pmatrix}0 & -0.5 \\ 0.5 & 0\end{pmatrix}. Coordinates are in cm.
    (a)
    (i) Find the coordinates of P1P_1 and P2P_2.
    (ii)
    R\mathbf{R} represents a rotation followed by an enlargement, both with centre the origin. Describe each fully.
    (iii) A triangle of area
    1212 cm2^2 is transformed by R\mathbf{R}. Find the area of its image.
    [6 marks]
    (b)
    (i) Find the distance P0P1P_0P_1.
    (ii) Explain why the distance
    Pn+1Pn+2P_{n+1}P_{n+2} is half the distance PnPn+1P_nP_{n+1} for every nn.
    (iii) Hence find the total length of the infinite path
    P0P1P2P3…P_0P_1P_2P_3\ldots
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).