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1.14 MatricesIB Maths: Applications and Interpretation HL: Subtopic test

10 questions, 27 marks

IB Maths: Applications and Interpretation HL

1.14 Matrices

Total 27 marks

Name

Class

Date

  1. 1
    A=(2134)A=\begin{pmatrix}2&1\\ 3&4\end{pmatrix} and B=(10−12)B=\begin{pmatrix}1&0\\ -1&2\end{pmatrix}.
    (a)
    Find ABAB.
    [1 mark]
    • A(20−38)\begin{pmatrix}2&0\\ -3&8\end{pmatrix}
    • B(2147)\begin{pmatrix}2&1\\ 4&7\end{pmatrix}
    • C(12−18)\begin{pmatrix}1&2\\ -1&8\end{pmatrix}
    • D(3126)\begin{pmatrix}3&1\\ 2&6\end{pmatrix}
    (b)
    Find det⁡A\det A.
    [1 mark]
    • A55
    • B1111
    • C−5-5
    • D15\frac{1}{5}
    (c)
    Find BABA and hence state, with a reason, whether AB=BAAB=BA.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A cafe sells small cups of coffee at ss EUR each and large cups at ll EUR each. On Monday, 3 small and 2 large cups cost 13.90 EUR in total. On Tuesday, 2 small and 5 large cups cost 21.00 EUR in total.
    (a)
    Which matrix equation represents this information?
    [1 mark]
    • A(3225)(sl)=(13.921)\begin{pmatrix}3&2\\ 2&5\end{pmatrix}\begin{pmatrix}s\\ l\end{pmatrix}=\begin{pmatrix}13.9\\ 21\end{pmatrix}
    • B(3252)(sl)=(13.921)\begin{pmatrix}3&2\\ 5&2\end{pmatrix}\begin{pmatrix}s\\ l\end{pmatrix}=\begin{pmatrix}13.9\\ 21\end{pmatrix}
    • C(3225)(sl)=(2113.9)\begin{pmatrix}3&2\\ 2&5\end{pmatrix}\begin{pmatrix}s\\ l\end{pmatrix}=\begin{pmatrix}21\\ 13.9\end{pmatrix}
    • D(3225)(ls)=(13.921)\begin{pmatrix}3&2\\ 2&5\end{pmatrix}\begin{pmatrix}l\\ s\end{pmatrix}=\begin{pmatrix}13.9\\ 21\end{pmatrix}
    (b)
    Find the determinant of the coefficient matrix (3225)\begin{pmatrix}3&2\\ 2&5\end{pmatrix}.
    [1 mark]
    • A1919
    • B1111
    • C−11-11
    • D111\frac{1}{11}
    (c)
    Use x=A−1b\mathbf{x}=A^{-1}\mathbf{b} with your GDC, where AA is the coefficient matrix, to find the price of a small cup and of a large cup.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Letters are replaced by numbers (A=1A=1, B=2B=2, ..., Z=26Z=26) and a message is coded in pairs of letters. Each pair of numbers forms a column vector, which is multiplied on the left by the matrix K=(2312)K=\begin{pmatrix}2&3\\ 1&2\end{pmatrix} to give the coded pair.
    (a)
    Show that det⁡K=1\det K=1 and find K−1K^{-1}.
    [3 marks]
    (b)
    A message is coded as the matrix C=(41622341)C=\begin{pmatrix}41&62\\ 23&41\end{pmatrix}, where each column is one coded pair. Find the original message.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A school shop sells pencils, pens and notebooks. Pencils cost pp EUR each, pens cost qq EUR each and notebooks cost rr EUR each. Class X buys 10 pencils, 4 pens and 2 notebooks for 14.60 EUR. Class Y buys 6 pencils, 5 pens and 3 notebooks for 16.20 EUR. Class Z buys 4 pencils, 2 pens and 6 notebooks for 18.80 EUR.
    (a)
    (i) Write down a matrix equation of the form Ax=bA\mathbf{x}=\mathbf{b} for x=(pqr)\mathbf{x}=\begin{pmatrix}p\\ q\\ r\end{pmatrix}.
    (ii) Use your GDC to find
    pp, qq and rr.
    [6 marks]
    (b)
    Let A=(1042653426)A=\begin{pmatrix}10&4&2\\ 6&5&3\\ 4&2&6\end{pmatrix} be the numbers of items bought by the three classes, and b=(14.616.218.8)\mathbf{b}=\begin{pmatrix}14.6\\ 16.2\\ 18.8\end{pmatrix} the amounts paid in EUR. The shop pays its supplier 0.30 EUR for each pencil, 0.70 EUR for each pen and 1.50 EUR for each notebook, written as the column vector c\mathbf{c}.
    (i) Calculate
    AcA\mathbf{c} and hence the profit on each class's purchase.
    (ii) Find the shop's total profit on the three purchases.

    (iii) Explain why
    cA\mathbf{c}A cannot be calculated.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).