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Algebraic expressions and substitutionIB MYP Maths Extended: Subtopic test

10 questions, 27 marks

IB MYP Maths Extended

Algebraic expressions and substitution

Total 27 marks

Name

Class

Date

  1. 1
    A taxi company in Nairobi charges C=50+30dC=50+30d shillings for a journey of dd kilometres.
    (a)
    Find the cost of a journey of 6 km.
    [1 mark]
    • A230230 shillings
    • B480480 shillings
    • C180180 shillings
    • D8686 shillings
    (b)
    A journey costs 410 shillings. Find its length.
    [1 mark]
    • A360360 km
    • B132313\frac{2}{3} km
    • C1212 km
    • D151315\frac{1}{3} km
    (c)
    A second journey is twice as long as one of dd km, so it is 2d2d km. Write a simplified expression for the total cost, in shillings, of one journey of dd km and one journey of 2d2d km.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Let a=3a=3, b=−2b=-2 and c=5c=5.
    (a)
    Find the value of a2+bca^2+bc.
    [1 mark]
    • A1919
    • B−1-1
    • C−4-4
    • D−19-19
    (b)
    Find the value of (a−b)2(a-b)^2.
    [1 mark]
    • A55
    • B1313
    • C11
    • D2525
    (c)
    Find the value of c−ba−b\frac{c-b}{a-b}.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A school hall is a rectangle of length (2x+3)(2x+3) metres and width (x+4)(x+4) metres. A square stage of side xx metres is built inside the hall.
    (a)
    Show that the area of the hall is 2x2+11x+122x^2+11x+12 square metres.
    [3 marks]
    (b)
    Find a simplified expression for the area of the hall not covered by the stage. Hence find this area when x=5x=5.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Mei investigates what happens when she picks a whole number nn, multiplies the numbers n−1n-1 and n+1n+1 on either side of it, and compares the answer with n2n^2. For n=6n=6 she gets 5×7=355\times7=35, which is 1 less than 62=366^2=36.
    (a)
    (i) Find (n−1)(n+1)(n-1)(n+1) and n2−(n−1)(n+1)n^2-(n-1)(n+1) when n=9n=9 and when n=12n=12.
    (ii) State the pattern as a general rule.

    (iii) Prove that the rule is true for every whole number
    nn by expanding (n−1)(n+1)(n-1)(n+1).
    [6 marks]
    (b)
    Mei now compares (n−2)(n+2)(n-2)(n+2) with n2n^2.
    (i) Expand and simplify
    (n−2)(n+2)(n-2)(n+2), and state how much less it is than n2n^2.
    (ii) Use your result with
    n=100n=100 to calculate 98×10298\times102 without a calculator.
    (iii) Write down, in terms of
    kk, how much less (n−k)(n+k)(n-k)(n+k) is than n2n^2.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).