Kinematics with vectors in two dimensionsEdexcel A-Level Maths: Flashcards

What these 12 flashcards ask

State the constant-acceleration formulae in vector form.
How do you find speed from \mathbf{v}=vx\mathbf{i}+vy\mathbf{j}?
What does 'moving parallel to \mathbf{i}' tell you about \mathbf{v}?
How do you find velocity from a position vector \mathbf{r}(t)?
How do you find acceleration from a velocity vector \mathbf{v}(t)?
Why must you add a constant when integrating \mathbf{a} to find \mathbf{v}?
Displacement between points A and B?
How do you find the angle the velocity makes with \mathbf{i}?
When can you use \mathbf{v}=\mathbf{u}+\mathbf{a}t?
\mathbf{u}=2\mathbf{i}-3\mathbf{j}, \mathbf{a}=4\mathbf{i}+2\mathbf{j}. Find \mathbf{v} at t=3.
Is a particle at rest when only one component of \mathbf{v} is zero?
What does 'on the line through O parallel to \mathbf{i}' mean for \mathbf{r}?

Exam questions on Kinematics with vectors in two dimensions

A particle $P$ moves in a horizontal plane with constant acceleration $(4\mathbf{i}+2\mathbf{j})$ m s $^{-2}$ . At time $t=0$ its velocity is $(2\mathbf{i}-3\mathbf{j})$ m s $^{-1}$ .
Find the value of $t$ at which $P$ is moving in the direction of $\mathbf{i}$ .2 marks
A particle $Q$ moves in a plane. Its position vector relative to a fixed origin $O$ at time $t$ seconds is $\mathbf{r}=(t^3-6t)\mathbf{i}+(4t^2-3t)\mathbf{j}$ metres, for $t\ge0$ .
Find the value of $t$ at which $Q$ is moving in the direction of $\mathbf{j}$ .2 marks
At time $t=0$ a particle is at the point $A$ with position vector $(3\mathbf{i}-2\mathbf{j})$ m, moving with velocity $(5\mathbf{i}+2\mathbf{j})$ m s $^{-1}$ . The particle moves with constant acceleration. At time $t=4$ s it is at the point $B$ with position vector $(35\mathbf{i}+14\mathbf{j})$ m.
Find the acceleration of the particle.3 marks

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).