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Newton-Raphson methodEdexcel A-Level Maths: Flashcards

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State the Newton-Raphson formula.

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State the Newton-Raphson formula.
xn+1=xn−f(xn)f′(xn)x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}
What does xn+1x_{n+1} represent geometrically?
The xx-intercept of the tangent to y=f(x)y=f(x) at x=xnx=x_n.
Newton-Raphson for f(x)=x2−7f(x)=x^2-7?
xn+1=12(xn+7xn)x_{n+1}=\frac12\left(x_n+\frac{7}{x_n}\right)
f(x)=x3−2x−5f(x)=x^3-2x-5 with x0=2x_0=2: find x1x_1.
2−−110=2.12-\frac{-1}{10}=2.1
f′(x)f'(x) for f(x)=ex−3xf(x)=\mathrm{e}^x-3x?
ex−3\mathrm{e}^x-3
When does Newton-Raphson fail completely?
When f′(xn)=0f'(x_n)=0: the tangent is horizontal and has no xx-intercept.
Why is a small f′(xn)f'(x_n) a problem?
The tangent is nearly horizontal, so xn+1x_{n+1} is far from the root.
What can happen with f(x)=x3−2x+2f(x)=x^3-2x+2 and x0=0x_0=0?
The iterates cycle 0,1,0,1,…0,1,0,1,\ldots and never converge.
How do you choose a good x0x_0?
Use a sign change to locate the root, then start close to it where f′f' is not small.
Is Newton-Raphson a recurrence relation xn+1=g(xn)x_{n+1}=g(x_n)?
Yes, with g(x)=x−f(x)f′(x)g(x)=x-\frac{f(x)}{f'(x)}.
Newton-Raphson can converge to a different root. Why?
The start value may lie nearer to (or in the basin of) another root.
When does xn+1=xnx_{n+1}=x_n?
Only when f(xn)=0f(x_n)=0, i.e. xnx_n is already a root.

Exam questions on Newton-Raphson method

  1. The equation f(x)=0f(x)=0, where f(x)=x3−2x−5f(x)=x^3-2x-5, has a root α\alpha near x=2x=2. The Newton-Raphson method is used with x0=2x_0=2.
    Find x2x_2, giving your answer to 4 decimal places.2 marks
  2. Let f(x)=ex−3xf(x)=\mathrm{e}^x-3x. The equation f(x)=0f(x)=0 has a root α\alpha close to 0.60.6, and the Newton-Raphson method is used with x0=0.5x_0=0.5.
    Given that x1=0.610060…x_1=0.610060\ldots, find x2x_2 to 4 decimal places.2 marks
  3. The Newton-Raphson method is used to find 7\sqrt7, as the positive root of x2−7=0x^2-7=0, starting from x0=3x_0=3.
    Show that the Newton-Raphson formula for this equation simplifies to xn+1=12(xn+7xn)x_{n+1}=\frac12\left(x_n+\frac{7}{x_n}\right), and find x1x_1 as an exact fraction.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).