Antiparticles, photons and annihilationAQA A-Level Physics: Revision notes
Section 1
Particles and their antiparticles
For every type of particle there is a corresponding antiparticle. An antiparticle has the same mass (and so the same rest energy) as its particle but opposite charge. Particles with no charge, such as the neutron and neutrino, have antiparticles with no charge too, but they are still different particles.
The antiparticles you need to know are:
- electron e⁻ → positron e⁺
- proton p → antiproton
- neutron n → antineutron
- neutrino → antineutrino
When a particle and its antiparticle meet they annihilate.
An antiparticle is not just 'the opposite charge'. The neutron and antineutron are both neutral but are still different particles.
Section 2
Comparing masses, charges and rest energies
Rest energy is the energy equivalent of a particle's mass, and for particles it is quoted in MeV. A particle and its antiparticle always have the same rest energy.
- electron and positron: 0.511 MeV, charge −1e and +1e
- proton and antiproton: about 938 MeV, charge +1e and −1e
- neutron and antineutron: about 940 MeV, both uncharged
- neutrino and antineutrino: negligible rest energy, both uncharged
To convert, 1 MeV = 1.60 × 10⁻¹³ J. You are not required to use E = mc² in calculations: rest energies are given or are in the data booklet.
Forgetting to convert MeV to joules before using E = hf. MeV must become J (× 1.60 × 10⁻¹³) first.
Section 3
The photon model
Electromagnetic radiation travels as discrete packets of energy called photons. The energy of one photon is
where J s is the Planck constant, is the frequency in Hz, m s⁻¹ and is the wavelength in m.
A higher frequency (shorter wavelength) means more energy per photon. Gamma-ray photons carry energies of the order of MeV.
Section 4
Annihilation
In annihilation a particle and its antiparticle meet and their mass is converted into energy, carried away as photons.
For an electron and a positron at rest, the total rest energy is 2 × 0.511 = 1.022 MeV. At least two photons are produced, travelling in opposite directions so that momentum is conserved. Each has energy 0.511 MeV (plus half of any kinetic energy the particles had).
Worked example. Each photon has E = 0.511 MeV = 8.18 × 10⁻¹⁴ J. Frequency Hz.
Section 5
Pair production
Pair production is the reverse: a photon with enough energy disappears (usually near a nucleus) and produces a particle and its antiparticle.
The photon energy must be at least twice the rest energy of one particle: 1.022 MeV for an electron and a positron, 1876 MeV for a proton and an antiproton. Any extra energy becomes the kinetic energy of the pair.
Charge is conserved: the photon is neutral, so the two particles carry opposite charges.
Annihilation and pair production are mirror images. Quote the energy conversion each way: mass to photon energy, and photon energy to mass plus kinetic energy.
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Antiparticles, photons and annihilation
- A positron emission tomography (PET) scanner uses a tracer that emits positrons inside a patient. Each positron quickly meets an electron in the tissue and the pair annihilate, producing two gamma-ray photons that are detected by a ring of sensors around the patient. The rest energy of an electron is 0.511 MeV.Explain why the annihilation of an electron and a positron at rest produces two photons rather than one, and why the photons travel in opposite directions.2 marks
- In a bubble chamber experiment, a gamma-ray photon of energy 1.50 MeV travels through liquid hydrogen. Close to a nucleus it disappears and a pair of particles is produced. The rest energy of an electron is 0.511 MeV.Calculate the longest wavelength of photon that could produce an electron–positron pair. Give your answer in metres.2 marks
- Physicists at a research laboratory study the production and annihilation of proton–antiproton pairs. The rest energy of a proton is 938 MeV, and an antiproton has the same rest energy.Calculate the minimum frequency of a photon that can produce a proton–antiproton pair.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).