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Progressive wavesAQA A-Level Physics: Revision notes

Section 1

Oscillating particles and energy transfer

A progressive wave transfers energy from one place to another through a medium without transferring the medium itself. Each particle (or each point in a field) oscillates about a fixed equilibrium position and passes its motion on to its neighbour, a little later.

The oscillation of every particle has the same frequency as the source, and, if energy losses are negligible, the same amplitude. What travels along the medium is the pattern of displacement, and with it the energy.

Key termsprogressive waveoscillationequilibrium position
Exam tip

On a rope or water wave, imagine a cork or a marked point: it bobs up and down on the spot while the wave moves past it.

Section 2

Describing a wave: amplitude, period, frequency, wavelength, speed

  • Displacement is the distance of a point from its equilibrium position, in a stated direction.
  • Amplitude AA is the maximum displacement from the equilibrium position.
  • Wavelength λ\lambda is the shortest distance along the wave between two points oscillating in phase, for example crest to crest.
  • Period TT is the time for one complete oscillation of a point; frequency ff is the number of oscillations per second, measured in hertz (Hz).
  • Wave speed cc (or vv) is the speed at which the wave pattern, and its energy, travels.

Period and frequency are linked by f=1Tf = \dfrac{1}{T}.

Key termsdisplacementamplitudewavelengthperiodfrequencywave speed
Common mistake

Amplitude is measured from the equilibrium position to a crest, not from crest to trough. Crest to trough is twice the amplitude.

Section 3

The wave equation

In one period TT the wave travels one wavelength λ\lambda, so the speed is c=λTc = \dfrac{\lambda}{T}. Using f=1/Tf = 1/T this gives the wave equation

c=fλc = f\lambda

The speed depends on the medium (and, for a string, on tension and mass per unit length), not on the source. If the frequency is changed while the medium stays the same, the wavelength changes so that cc stays constant: doubling ff halves λ\lambda.

Worked example. Water waves of frequency 12 Hz have wavelength 2.5 cm. Then c=fλ=12×0.025=0.30 m s−1c = f\lambda = 12 \times 0.025 = 0.30\ \text{m s}^{-1}. Always convert the wavelength to metres first.

Key termswave equation
Exam tip

Rearrange before substituting: λ = c/f, f = c/λ. Check units: Hz × m = m s⁻¹.

Section 4

Phase and phase difference

The phase of a point is the stage it has reached in its oscillation cycle. Two points on a wave are in phase if they are at the same stage of the cycle, so they have the same displacement and move in the same direction at the same time.

The phase difference between two oscillations measures how much one is ahead of or behind the other. It can be given as:

  • a fraction of a cycle, e.g. 1/4 cycle
  • an angle in degrees, where one cycle is 360°360°
  • an angle in radians, where one cycle is 2π2\pi rad.

Points a whole number of wavelengths apart are in phase (phase difference 00, 2π2\pi, 4π4\pi, …). Points an odd number of half wavelengths apart are in antiphase (phase difference π\pi, 3π3\pi, …): they always move in opposite directions.

Key termsphasephase differencein phaseantiphase
Common mistake

A phase difference of 1/4 cycle is π/2 rad, not 1/4 rad. Multiply the fraction of a cycle by 2π (or by 360°).

Section 5

Calculating phase difference between two points

Two points a distance xx apart along a progressive wave of wavelength λ\lambda have a phase difference

Δϕ=xλ×2π (radians)orxλ×360°.\Delta\phi = \frac{x}{\lambda} \times 2\pi \ \text{(radians)} \qquad\text{or}\qquad \frac{x}{\lambda}\times 360° .

The point further from the source lags: it repeats the motion of the nearer point after a time x/cx/c has passed.

Worked example. A wave of wavelength 8.0 m travels at 4.0 m s⁻¹. Two points 3.0 m apart are 3.0/8.0=3/83.0/8.0 = 3/8 of a cycle out of phase, so Δϕ=38×2π=3π4=2.4\Delta\phi = \tfrac{3}{8}\times 2\pi = \tfrac{3\pi}{4} = 2.4 rad (135°). The time lag is 3.0/4.0=0.753.0/4.0 = 0.75 s, which is 3/8 of the period (2.0 s), as expected.

Key termslag

Must Know

  • A progressive wave transfers energy by oscillation of particles or fields; the medium does not travel along
  • c=fλc = f\lambda and f=1/Tf = 1/T
  • Amplitude is the maximum displacement from equilibrium
  • Wave speed is fixed by the medium, so doubling ff halves λ\lambda
  • In phase: whole number of wavelengths apart; antiphase: odd number of half wavelengths apart
  • Phase difference = (separation ÷ wavelength) × 2π2\pi rad, or × 360°

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Exam questions on Progressive waves

  1. A student uses a vibrating dipper to generate straight water waves in a ripple tank. The dipper vibrates at 12 Hz and the student measures the distance between adjacent wave crests on the water surface as 2.5 cm.
    The student doubles the frequency of the dipper. The speed of the waves is unchanged because the depth of water is unchanged. Calculate the new wavelength.2 marks
  2. Two buoys, A and B, float on a lake in line with the direction in which a sinusoidal water wave is travelling. The wave has frequency 0.50 Hz and wavelength 8.0 m. Buoy B is 3.0 m further along the direction of travel than buoy A.
    Calculate the time by which the motion of buoy B lags behind that of buoy A.2 marks
  3. A loudspeaker produces a continuous pure note of frequency 850 Hz in air, where the speed of sound is 340 m s⁻¹. Two small microphones are placed in a straight line with the loudspeaker, at distances of 1.20 m and 1.50 m from it.
    Calculate the wavelength of the sound and the phase difference, in radians, between the signals at the two microphones.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).