Conservation laws in particle interactionsAQA A-Level Physics: Revision notes
Section 1
Quark character in beta decay
In beta-minus decay a neutron changes into a proton, so a down quark changes into an up quark:
n → p + e⁻ + (udd → uud)
In beta-plus decay a proton changes into a neutron, so an up quark changes into a down quark:
p → n + e⁺ + (uud → udd)
Quark charges are +⅔ (up) and −⅓ (down). The change in quark charge is carried away by the emitted electron or positron.
Beta-minus emits an electron and an antineutrino. Beta-plus emits a positron and a neutrino. Check lepton number to remember which.
Section 2
Conserved quantities
In every interaction in these questions the following are conserved:
- Charge: the total charge before equals the total after
- Baryon number: baryons +1, antibaryons −1, mesons and leptons 0
- Lepton number: leptons +1, antileptons −1. The electron family (e⁻, ) and the muon family (μ⁻, ) are counted separately
- Strangeness: strange quark −1, anti-strange +1. The data you need for other particles is given in the question
The energy and momentum of the whole system are also conserved.
Section 3
Applying the conservation laws
To test whether an interaction can occur, add up each quantity on each side and compare.
Worked example: π⁻ + p → K⁰ + Λ⁰
- Charge: (−1) + (+1) = 0 before; 0 + 0 = 0 after ✓
- Baryon number: 0 + 1 = 1 before; 0 + 1 = 1 after ✓
- Strangeness: 0 + 0 = 0 before; (+1) + (−1) = 0 after ✓
All quantities balance, so the interaction is allowed. If any one quantity does not balance, the interaction cannot occur.
Do not just say a quantity is conserved. Write the totals before and after, with numbers, for every quantity you check.
Section 4
Finding an unknown particle
If one particle in an interaction is unknown, use the conservation laws to work out its properties.
Example: π⁻ → μ⁻ + ?
- Charge: −1 → −1 + ?, so the unknown is neutral
- Muon lepton number: 0 → +1 + ?, so the unknown has −1
The unknown particle is a muon antineutrino.
In beta-minus decay the electron has electron lepton number +1, so the second particle must be an electron antineutrino to keep the total at 0.
Section 5
Energy and momentum
Energy is conserved in every interaction: the total energy, including rest energy and kinetic energy, is the same before and after. A decay can only happen if the products have no more rest energy than the particle that decays. A collision that creates new particles needs enough kinetic energy to supply their rest energy.
Momentum is also conserved. In beta decay the electron is emitted with a range of kinetic energies, so a third particle (the antineutrino in beta-minus decay) must share the energy and momentum.
Must Know
- β⁻: d → u + e⁻ + ; β⁺: u → d + e⁺ +
- Charge, baryon number, lepton number (by family) and strangeness are conserved in these interactions
- Show totals before and after for each quantity
- Energy and momentum are conserved in all interactions
- Strangeness must balance in the collisions studied; use the data given
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Conservation laws in particle interactions
- Caesium-137 in stored nuclear waste decays by beta-minus emission. Inside each decaying nucleus a neutron changes into a proton, and an electron is emitted at high speed together with one other, very weakly interacting, particle.Show that charge and baryon number are both conserved in the decay n → p + e⁻ + .2 marks
- A positron emission tomography (PET) scanner uses a tracer containing fluorine-18. Each fluorine-18 nucleus decays by beta-plus emission: a proton in the nucleus changes into a neutron and a positron is emitted together with a neutrino.A free proton does not decay in this way, although a proton inside some nuclei can. Using conservation of energy, explain why.2 marks
- At a particle accelerator a beam of negative pions is fired into a target of liquid hydrogen, so that pions collide with protons. Data: a pion π⁻ has charge −1, baryon number 0 and strangeness 0; a proton has charge +1, baryon number +1 and strangeness 0. The Λ⁰ has charge 0, baryon number +1 and strangeness −1. The K⁰ has charge 0, baryon number 0 and strangeness +1. The K⁻ has charge −1, baryon number 0 and strangeness −1. The Σ⁺ has charge +1, baryon number +1 and strangeness −1. Strangeness is conserved in these collisions.Show that the interaction π⁻ + p → K⁰ + Λ⁰ obeys the conservation of charge, baryon number and strangeness.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).