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Particle accelerators and detectorsEdexcel International A Level Physics: Revision notes

Section 1

Thermionic emission and electric fields

When a metal filament is heated, some of its conduction electrons gain enough kinetic energy to escape from the surface. This is thermionic emission. The apparatus must be evacuated so that the electrons are not scattered by air and the filament does not burn away.

A charged particle in a uniform electric field is accelerated by the force F=QEF = QE. If a particle of charge QQ is accelerated from rest through a potential difference VV it gains kinetic energy

12mv2=QV\frac{1}{2}mv^2 = QV

For electrons accelerated through 1500 V: v=2eVm=2×1.60×10−19×15009.11×10−31=2.3×107v = \sqrt{\frac{2eV}{m}} = \sqrt{\frac{2 \times 1.60 \times 10^{-19} \times 1500}{9.11 \times 10^{-31}}} = 2.3 \times 10^{7} m s⁻¹.

Key termsthermionic emission

Section 2

Magnetic fields and circular motion

A magnetic field exerts a force F=BQvF = BQv perpendicular to the velocity of a charge moving at right angles to the field. The force does no work, so the speed does not change, but the direction does. The particle is accelerated (its velocity changes) and moves in a circle.

The magnetic force provides the centripetal force:

BQv=mv2rBQv = \frac{mv^2}{r} so r=mvBQ=pBQr = \frac{mv}{BQ} = \frac{p}{BQ}

The radius is proportional to the momentum and inversely proportional to BB and QQ. A particle with twice the charge and the same momentum moves on a circle of half the radius.

Key termsr = p/BQ
Exam tip

Derive r = p/BQ in three lines: BQv = mv²/r, so r = mv/BQ, and mv = p.

Section 3

The linear accelerator (linac)

A linac has a line of hollow metal drift tubes in a vacuum, joined alternately to the terminals of a high-frequency alternating supply.

  • the electric field in the gaps accelerates the charged particles
  • inside a tube there is no field, so the particles move at constant speed
  • the p.d. reverses while the particles are inside a tube, so they are accelerated again at the next gap
  • the particles move faster, so the tubes get longer: each tube takes half a period of the supply

Particles are accelerated in a straight line, so no magnetic field is needed.

Key termslinac

Section 4

The cyclotron

A cyclotron has two hollow D-shaped metal dees in a vacuum with a small gap between them. A uniform magnetic field acts perpendicular to the dees and an alternating p.d. is applied across the gap.

  • particles are accelerated by the electric field each time they cross the gap
  • inside each dee there is no electric field; the magnetic field bends the path into a semicircle
  • as the speed rises, r=mvBQr = \frac{mv}{BQ} increases, so the particles spiral outwards
  • the time per semicircle πrv=πmBQ\frac{\pi r}{v} = \frac{\pi m}{BQ} is constant, so the frequency of the supply, f=BQ2πmf = \frac{BQ}{2\pi m}, can stay fixed

The particles leave at the edge with the maximum radius.

Key termscyclotron

Section 5

Detectors

Charged particles passing through a detector (for example a cloud chamber, bubble chamber or Geiger tube) ionise the atoms along their path, leaving a visible or measurable trail.

  • a perpendicular magnetic field deflects the particles; the direction of curvature shows the sign of the charge
  • the radius of curvature gives the momentum, using r=pBQr = \frac{p}{BQ}
  • a particle that loses energy by ionisation slows down, so its track spirals inwards
  • neutral particles leave no track, as they do not ionise directly
Key termsionisation
Common mistake

Do not say the magnetic field speeds up a particle in a cyclotron. The electric field in the gap does the accelerating; the magnetic field only bends the path.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Particle accelerators and detectors

  1. An electron gun in an evacuated tube has a heated tungsten filament. Electrons released from the filament are accelerated through a potential difference of 1500 V between the filament and a metal anode.
    Explain why the electron gun must be evacuated.2 marks
  2. A cyclotron accelerates protons using two hollow D-shaped metal electrodes (dees) separated by a small gap. A uniform magnetic field of flux density 1.2 T acts perpendicular to the plane of the dees, and an alternating potential difference is applied across the gap.
    Explain why the radius of the path increases as the protons gain speed, but the time taken for each semicircle stays the same.2 marks
  3. A proton moves in a uniform magnetic field of flux density 1.5 T that is perpendicular to its velocity, in a bubble chamber. It leaves a circular track of radius 0.085 m. The proton charge is 1.60 × 10⁻¹⁹ C.
    Calculate the momentum of the proton.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).