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The ideal gas equation and kinetic theoryEdexcel International A Level Physics: Revision notes

Section 1

The ideal gas equation

For an ideal gas the pressure p, volume V, number of molecules N and absolute temperature T are linked by

pV=NkTpV = NkT

where k=1.38×10−23k = 1.38 \times 10^{-23} J K⁻¹ is the Boltzmann constant. T must be in kelvin, p in pascals and V in m³.

It is equivalent to pV = nRT, with N = nN_A and R = N_Ak.

Worked example: a 2.0 × 10⁻³ m³ flask at 1.0 × 10⁵ Pa and 300 K holds N = pV/kT = 4.8 × 10²² molecules.

Key termsideal gasBoltzmann constant
Common mistake

Do not use Celsius temperatures in pV = NkT. Convert to kelvin first.

Section 2

Using the equation

At a fixed N, rearranging gives pV/T = constant, so:

  • constant T: pV is constant (Boyle's law), so p1V1=p2V2p_1V_1 = p_2V_2
  • constant V: p is proportional to T
  • constant p: V is proportional to T

The ratio of two states needs only ratios of volumes or pressures, so unit conversions cancel, but T must still be in kelvin.

Key termsBoyle's law

Section 3

Core practical 14: pressure and volume

To investigate the relationship between pressure and volume at constant temperature:

  • Trap a fixed mass of air in a syringe connected to a pressure gauge.
  • Change the volume slowly with the plunger and wait before each reading so that the air returns to room temperature.
  • Record p and V, and repeat.
  • Plot p against 1/V. A straight line through the origin shows that pV is constant.

Compressing quickly warms the gas, and leaks change the mass of gas, so these are the main sources of error.

Key termsconstant temperature
Exam tip

Say 'slowly, then wait' when asked how to keep temperature constant.

Section 4

Kinetic theory and mean kinetic energy

Kinetic theory models the pressure of a gas as the result of many molecular collisions with the walls, giving

pV=13Nm⟨c2⟩pV = \tfrac{1}{3}Nm\langle c^2\rangle

where ⟨c²⟩ is the mean square speed.

Derivation: equate this with NkT, divide by N and multiply by 3/2:

12m⟨c2⟩=32kT\tfrac{1}{2}m\langle c^2\rangle = \tfrac{3}{2}kT

The left side is the mean kinetic energy of one molecule. It depends only on the absolute temperature, so doubling T doubles the mean kinetic energy.

Key termsmean square speedroot mean square speed

Section 5

Worked example: speed of molecules

Find c_rms for nitrogen (molecule mass 4.65 × 10⁻²⁶ kg) at 300 K.

Mean kinetic energy = (3/2)kT = 6.2 × 10⁻²¹ J.

⟨c²⟩ = 2 × 6.2 × 10⁻²¹ / 4.65 × 10⁻²⁶ = 2.7 × 10⁵ m² s⁻²

c_rms = 5.2 × 10² m s⁻¹.

At the same temperature all gases have the same mean kinetic energy per molecule, so lighter molecules have a larger c_rms.

Key termsc_rms
Common mistake

The mean kinetic energy is the same for all gases at one temperature. It is the speeds that differ.

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Exam questions on The ideal gas equation and kinetic theory

  1. A sealed flask of volume 2.0 × 10⁻³ m³ contains an ideal gas at a pressure of 1.0 × 10⁵ Pa and a temperature of 300 K. The Boltzmann constant is k = 1.38 × 10⁻²³ J K⁻¹.
    Calculate the mean kinetic energy of a molecule of the gas.2 marks
  2. A class investigates the relationship between the pressure and volume of a fixed mass of air at constant temperature. The air is trapped in a syringe connected to a pressure gauge, and the students change the volume with the plunger and record the pressure each time.
    The air is at a pressure of 1.00 × 10⁵ Pa when its volume is 60 cm³. The students compress it to 24 cm³ at constant temperature. Calculate the new pressure.2 marks
  3. Helium is used to fill a weather balloon. A helium atom has mass 6.64 × 10⁻²⁷ kg. The gas can be treated as ideal and is at a temperature of 300 K. The Boltzmann constant is k = 1.38 × 10⁻²³ J K⁻¹. Argon atoms have a mass of 6.63 × 10⁻²⁶ kg.
    Calculate the root mean square speed of the helium atoms.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).