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Wave properties and the wave equationEdexcel International A Level Physics: Revision notes

Section 1

Describing a wave

A wave transfers energy without transferring matter.

  • Amplitude (A): the maximum displacement from the equilibrium position
  • Wavelength (λ): the distance between two adjacent points that are in phase, such as adjacent crests
  • Period (T): the time for one complete oscillation
  • Frequency (f): the number of oscillations per second, in hertz; f = 1/T
  • Speed (v): the distance travelled by the wave per second

The wave equation is v = fλ.

Worked example: sound of frequency 680 Hz travels at 340 m s⁻¹, so λ = v/f = 340 / 680 = 0.50 m.

Key termsamplitudefrequencyperiodwavelengthwave speed
Common mistake

Speed depends on the medium, not the frequency. If f changes while v stays constant, λ changes.

Section 2

Transverse waves

In a transverse wave the oscillations are perpendicular to the direction in which energy travels. Examples are waves on a string, ripples on water and electromagnetic waves.

Each point on a string moves up and down about its equilibrium position, while the wave pattern moves along the string. Crests and troughs are the points of maximum positive and negative displacement.

Key termstransverse wavecresttrough

Section 3

Longitudinal waves

In a longitudinal wave the oscillations are parallel to the direction of energy travel. Sound in air is an example.

  • Molecules oscillate backwards and forwards about fixed equilibrium positions: there is no net flow of air.
  • Compressions are regions of high pressure and rarefactions are regions of low pressure.
  • The wavelength is the distance between adjacent compressions (or adjacent rarefactions).

The pressure variation is a quarter of a cycle out of phase with the displacement of the molecules.

Key termslongitudinal wavecompressionrarefaction
Common mistake

Sound has compressions and rarefactions, not crests and troughs.

Section 4

Graphs of waves

Two graphs describe a wave:

  • Displacement against distance: a snapshot at one instant. It shows the wavelength (between adjacent crests) and the amplitude.
  • Displacement against time: the motion of one point. It shows the period (time for one cycle), from which f = 1/T.

For a longitudinal wave the displacement plotted is along the direction of travel (a sign convention for left or right), so the graph looks like that of a transverse wave but does not show the wave's shape.

A stationary (standing) wave has fixed points of zero displacement called nodes and points of maximum amplitude called antinodes; the displacement against distance graph shows this envelope. Adjacent nodes are half a wavelength apart.

Key termsnodeantinodestationary wave

Section 5

Core practical 4: the speed of sound in air

Connect a signal generator to a loudspeaker and to one channel of a two-beam oscilloscope. Connect a microphone to the other channel.

  1. Set a known frequency f.
  2. Move the microphone away from the speaker; the two traces move in and out of phase.
  3. Note positions where they are in phase. The distance between adjacent in-phase positions is one wavelength.
  4. Measure the distance across many wavelengths (for example 10) with a metre rule and divide, to reduce the percentage uncertainty.
  5. Calculate v = fλ; repeat at other frequencies and average, or plot λ against 1/f (gradient = v).
Key termsin phaseoscilloscope
Exam tip

Measuring across several wavelengths gives a smaller percentage uncertainty than measuring a single wavelength.

Must Know

  • v = fλ; f = 1/T
  • Transverse: oscillations perpendicular to travel; longitudinal: parallel
  • Sound: compressions and rarefactions, molecules oscillate about fixed positions
  • Distance graph gives λ; time graph gives T
  • Core practical 4: measure across many wavelengths, then v = fλ

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Wave properties and the wave equation

  1. A loudspeaker emits a continuous note of frequency 680 Hz in air, where the speed of sound is 340 m s⁻¹.
    The frequency of the loudspeaker is now doubled. State and explain what happens to the speed and to the wavelength of the sound.2 marks
  2. A ship's echo-sounder transmits pulses of ultrasound of frequency 50 kHz. The wavelength of the ultrasound in sea water is 3.0 cm.
    A pulse is transmitted vertically downwards and its echo from the sea bed is received 0.40 s later. Calculate the depth of the sea bed.2 marks
  3. A transverse wave travels along a long stretched string. The wave has amplitude 12 mm, frequency 25 Hz and wavelength 0.80 m. At time t = 0 a point P on the string is at its maximum positive displacement.
    Describe what is meant by a transverse wave and how the string moves as the wave passes along it.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).