Gravitational potential and comparison with electric fieldsEdexcel A-Level Physics: Revision notes
Section 1
Gravitational potential
The gravitational potential at a point is the work done per unit mass in moving a small mass from infinity to that point. It is measured in J kg⁻¹. It is a scalar, and it is defined to be zero at infinity.
Because gravity is attractive, the field does positive work as a mass moves in from infinity, so the potential at every finite distance is negative. Equivalently, work must be done on a mass to take it out to infinity.
For a point mass or uniform sphere of mass , at a distance from its centre:
The closer to the mass, the more negative becomes, so the potential increases as you move away from the mass.
Dropping the minus sign. At the Earth's surface V = −6.25×10⁷ J kg⁻¹, not +6.25×10⁷ J kg⁻¹.
Section 2
Potential energy and changes in potential
A mass at a point of potential has gravitational potential energy . When a mass moves between two points, the change in potential energy is:
If is positive (moving away from the mass) the object gains energy; the work done by an external force equals .
Potentials from several masses add as scalars, which is easier than adding fields as vectors.
Worked example: Raise 450 kg from the Earth's surface () to . J kg⁻¹, so J.
mgh works only for small changes in height where g is nearly constant. For large changes in height use ΔE = mΔV.
Section 3
Similarities between electric and gravitational fields
Both fields describe forces acting at a distance, and they share a mathematical form:
- Both are radial around a point source, with field lines pointing towards or away from it
- Both forces obey an inverse square law: and
- Field strength is force per unit of the property that feels the field: in N kg⁻¹, in N C⁻¹
- Field strength falls as : and
- Potential is zero at infinity, with and
The analogy is: mass charge and .
Section 4
Differences between electric and gravitational fields
- Gravitational force is always attractive; electric force can be attractive or repulsive, because there are two types of charge
- Gravitational potential is always negative; electric potential can be positive (near a positive charge) or negative (near a negative charge)
- Gravity depends on mass; the electric force depends on charge, and a body can be neutral
- Gravity is far weaker: the electric force between a proton and an electron is about times larger than the gravitational force
- Electric fields can be shielded by conductors or screened by opposite charges; gravitational fields cannot
Because planets and stars are almost electrically neutral, electric forces cancel and gravity dominates at large scales.
Section 5
Worked comparison: proton and electron
A proton and an electron are m apart.
Gravitational: N.
Electric: N.
The ratio of electric to gravitational force is about , and since both forces are inverse square the ratio does not depend on separation. This is why gravity is ignored in atomic physics.
Must know
- : work done per unit mass bringing a mass from infinity; zero at infinity; always negative; unit J kg⁻¹
- (use this instead of for large changes in height)
- Both fields are radial and inverse square; ,
- Gravity is only attractive; electric forces attract or repel
- Gravity is far weaker, and cannot be shielded
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Gravitational potential and comparison with electric fields
- An engineer is planning to launch a probe of mass 450 kg from the surface of the Earth. The Earth may be treated as a uniform sphere of mass 5.97×10²⁴ kg and radius 6.37×10⁶ m, and the gravitational constant is G = 6.67×10⁻¹¹ N m² kg⁻².The probe is raised from the surface of the Earth to a height equal to the radius of the Earth. Calculate the increase in the gravitational potential energy of the probe.2 marks
- In a simple model of a hydrogen atom, an electron of mass 9.11×10⁻³¹ kg and charge −1.60×10⁻¹⁹ C is a distance of 5.3×10⁻¹¹ m from a proton of mass 1.67×10⁻²⁷ kg and charge +1.60×10⁻¹⁹ C. Both particles are treated as point masses and point charges. Take G = 6.67×10⁻¹¹ N m² kg⁻² and ε₀ = 8.85×10⁻¹² F m⁻¹.Calculate the gravitational force between the proton and the electron.2 marks
- A lunar lander of mass 1200 kg is on the surface of the Moon. The Moon may be treated as a uniform sphere of mass 7.35×10²² kg and radius 1.74×10⁶ m. Take G = 6.67×10⁻¹¹ N m² kg⁻². The surface field strength of the Moon is 1.62 N kg⁻¹.Calculate the gravitational potential at the surface of the Moon and explain why the value is negative.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).