Density and upthrustEdexcel A-Level Physics: Revision notes
Section 1
Density
Density is the mass per unit volume of a substance:
where ρ is in kg m⁻³, m in kg and V in m³. Density depends on the material and not on the size of the sample, so cutting an object in half halves both m and V and leaves ρ unchanged.
Unit conversions matter: 1 g cm⁻³ = 1000 kg m⁻³, and 1 cm³ = 10⁻⁶ m³. Water has a density of about 1000 kg m⁻³.
Worked example: a block of 0.135 kg and volume 5.0 × 10⁻⁵ m³ has ρ = 0.135 / 5.0 × 10⁻⁵ = 2700 kg m⁻³.
Converting cm³ to m³ by dividing by 100 or 1000. A cubic conversion needs 10⁶ (1 cm³ = 10⁻⁶ m³).
Section 2
Where upthrust comes from
When an object is placed in a fluid (a liquid or a gas), the fluid exerts an upward force on it called upthrust. It arises because pressure in a fluid increases with depth, so the fluid pushes up on the lower surface of the object with a greater force than it pushes down on the upper surface. The resultant of these forces is directed upwards.
Section 3
Upthrust = weight of fluid displaced
The size of the upthrust is given by Archimedes' principle: the upthrust on an object equals the weight of fluid it displaces.
The fluid displaced has volume equal to the submerged volume of the object. A fully submerged object displaces its whole volume; a floating object displaces only the part below the surface.
Worked example: a sphere weighs 3.60 N in air and reads 2.25 N when fully in water. The upthrust is 3.60 − 2.25 = 1.35 N, so V = 1.35 / (1000 × 9.81) = 1.4 × 10⁻⁴ m³. Its density is (3.60 / 9.81) / 1.38 × 10⁻⁴ ≈ 2.7 × 10³ kg m⁻³.
Use the volume of the fluid displaced, not the volume of the whole object, unless the object is fully submerged.
Section 4
Floating, sinking and hovering
The motion of an object in a fluid depends on the balance between its weight W and the upthrust U:
- U = W: equilibrium. The object floats at rest on the surface, or hovers at constant depth if fully submerged.
- W > U when fully submerged: a downward resultant force, so the object sinks.
- U > W when fully submerged: an upward resultant force, so the object rises until it floats.
A floating object displaces just enough fluid to have a weight equal to its own weight. An object denser than the fluid cannot float, because even fully submerged the upthrust is smaller than its weight. A submarine changes its weight by flooding or emptying ballast tanks, while its volume, and so its maximum upthrust, stays fixed.
Must Know
- ρ = m/V, in kg m⁻³; density does not change when a sample is divided
- Upthrust = weight of fluid displaced = ρ_fluid V g
- Floating or hovering: upthrust = weight
- Fully submerged and W > U: sinks; U > W: rises
- Convert cm³ to m³ with 10⁻⁶
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Density and upthrust
- A technician investigates a rectangular block of aluminium measuring 0.050 m × 0.040 m × 0.025 m. The block has a mass of 0.135 kg.The block is cut into two equal halves. State what happens to the mass, volume and density of one half compared with the original block.2 marks
- A wooden block of mass 0.48 kg and total volume 8.0 × 10⁻⁴ m³ is placed in fresh water of density 1000 kg m⁻³. It floats at rest. Take g = 9.81 N kg⁻¹.Explain why the block floats with only part of its volume below the water surface.2 marks
- A metal sphere is hung from a newtonmeter. In air the reading is 3.60 N. The sphere is then lowered until it is fully submerged in water of density 1000 kg m⁻³, without touching the container, and the reading falls to 2.25 N. Take g = 9.81 N kg⁻¹.Calculate the volume of the sphere.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).