Current, potential difference and resistanceEdexcel A-Level Physics: Revision notes
Section 1
Electric current
Electric current is the rate of flow of charge:
I = Q / t
where Q is the charge in coulombs (C) and t is the time in seconds. The unit of current is the ampere (A); one ampere is one coulomb per second (C s⁻¹). In a metal the charge carriers are electrons, each with a charge of magnitude 1.60 × 10⁻¹⁹ C, so the number of electrons passing a point in time t is Q divided by the charge of one electron.
Worked example. A current of 2.0 A flows for 45 minutes. Q = It = 2.0 × 2700 = 5.4 × 10³ C.
Using the time in minutes. Convert to seconds before using Q = It.
Section 2
Potential difference
The potential difference (p.d.) between two points is the energy transferred per unit charge as charge moves between them:
V = W / Q
where W is the energy transferred (work done) in joules. The unit is the volt (V); one volt is one joule per coulomb (J C⁻¹). Rearranged, W = QV, and since Q = It, W = VIt.
Worked example. The charger above, at 5.0 V, transfers W = QV = 5.4 × 10³ × 5.0 = 2.7 × 10⁴ J.
Section 3
Resistance
The resistance of a component is the ratio of the p.d. across it to the current through it:
R = V / I
The unit is the ohm (Ω); one ohm is one volt per ampere. For a given p.d., a larger resistance gives a smaller current. Resistance is found for a particular p.d. and current: for a component where R changes, calculate it separately for each pair of readings, and do not use the gradient of the graph unless the line is a straight line through the origin.
Section 4
Ohm's law
Ohm's law states that the current through a conductor is directly proportional to the potential difference across it, provided the temperature is constant. A conductor that obeys it is ohmic. For an ohmic conductor, a graph of I against V is a straight line through the origin and R = V / I is constant.
Many components are non-ohmic. A filament lamp has a current-p.d. graph that curves, because the filament gets hotter as the current rises, so its resistance increases. In a metal the ions vibrate with greater amplitude at higher temperature, so electrons collide with them more often.
Saying Ohm's law is V = IR. That is the definition of resistance. Ohm's law is about proportionality at constant temperature.
Section 5
Testing Ohm's law
Connect the component in series with an ammeter, and a voltmeter in parallel across it. Vary the p.d. in steps using a variable power supply (or potential divider) and record the current at each value. Use small currents and allow time to cool so the temperature stays constant. Plot I against V, and calculate R = V / I for each reading.
A straight line through the origin means the component is ohmic. A curve with a changing R means it is not.
Must know
- I = Q / t, unit A (C s⁻¹); W = QV and V = W / Q, unit V (J C⁻¹)
- R = V / I, unit Ω (V A⁻¹)
- Ohm's law: I ∝ V at constant temperature
- Ohmic: straight line through the origin; filament lamp: R increases with temperature
- Ammeter in series, voltmeter in parallel
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Current, potential difference and resistance
- A phone charger delivers a constant current of 2.0 A at a potential difference of 5.0 V. A phone is charged for 45 minutes.Calculate the number of electrons that pass through the charger cable each second. The charge of an electron is 1.60 × 10⁻¹⁹ C.2 marks
- A student investigates a filament lamp. When the potential difference across the lamp is 6.0 V the current is 1.5 A, and when it is 12 V the current is 2.0 A.Use the data to explain why the filament lamp does not obey Ohm's law.2 marks
- The heating element of an electric kettle is connected to a 230 V supply. When the water is boiling the element carries a steady current of 8.7 A for 3.0 minutes.Calculate the charge that passes through the element and the energy it transfers in this time.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).