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Electrical power and I-V characteristicsEdexcel A-Level Physics: Revision notes

Section 1

Electrical power and energy

Power is the rate of energy transfer, and for an electrical component P = VI (watts = volts × amperes). The energy transferred in time t is W = VIt, which is just W = Pt.

Combining with V = IR gives two more forms:

  • P = I²R (best when the current is the same, e.g. components in series)
  • P = V²/R (best when the p.d. is the same, e.g. components in parallel or across a fixed supply)

Worked example: a 230 V, 2.3 kW kettle draws I = P/V = 2300/230 = 10 A. Its element has R = V²/P = 230²/2300 = 23 Ω. In 3.0 minutes it transfers W = 2300 × 180 = 4.1 × 10⁵ J.

Key termspowerP = VIW = VIt
Exam tip

Choose the power equation that uses the quantity you are given and the one that stays constant. At a fixed p.d., a lower resistance means more power; at a fixed current, a higher resistance means more power.

Section 2

Reading an I–V characteristic

An I–V characteristic plots current (y-axis) against p.d. (x-axis) for a component. The resistance at any point is R = V/I at that point.

For a straight line through the origin, the gradient is 1/R. For a curve, you must work out V/I at the point you are interested in. Do not use the gradient of a tangent as 1/R for a curved characteristic.

Always say whether the gradient is increasing or decreasing, then link it to what happens to resistance. A steeper line on an I–V graph means a lower resistance.

Key termsI–V characteristicresistance
Common mistake

On a curved I–V graph, resistance is V/I at a point, not 1/gradient of the tangent there. Using the tangent gives the wrong value.

Section 3

Ohmic conductor and filament lamp

An ohmic conductor (e.g. a metal wire at constant temperature) gives a straight line through the origin: I ∝ V, constant resistance. This is Ohm's law, and it only holds if the temperature stays constant.

A filament lamp gives a curve whose gradient decreases as p.d. rises, so resistance increases. The current heats the tungsten filament, so the metal ions vibrate with greater amplitude. Conduction electrons collide with the ions more often, lowering their drift velocity for the same p.d.

Both characteristics are symmetrical about the origin when the p.d. is reversed.

Key termsohmic conductorOhm's lawlattice vibrations

Section 4

NTC thermistor

A negative temperature coefficient (NTC) thermistor is a semiconductor whose resistance falls as its temperature rises. Heating releases more electrons from atoms, so the number of conduction electrons per unit volume (n) increases. This outweighs the extra lattice vibrations.

On an I–V graph, as p.d. and current rise the thermistor warms, its resistance falls and the curve becomes steeper.

At a fixed p.d., P = V²/R means falling resistance gives rising power and further heating. This positive feedback (thermal runaway) is why thermistors are often used with a series resistor.

Key termsNTC thermistorcharge carriers

Section 5

Diode

A diode conducts in one direction only. In the forward direction the current is almost zero until the p.d. reaches a threshold (about 0.6–0.7 V for silicon), then rises steeply and the resistance becomes very small.

In the reverse direction the current is almost zero (very high resistance) up to a large breakdown p.d.

Worked example: a silicon diode (0.70 V) in series with a 220 Ω resistor and a 6.0 V battery: p.d. across resistor = 5.3 V, so I = 5.3/220 = 0.024 A. Reversed, I ≈ 0 and almost all 6.0 V is across the diode.

Key termsdiodethreshold p.d.

Must Know

  • P = VI, W = VIt, P = I²R, P = V²/R
  • Ohmic conductor: straight line through the origin at constant temperature
  • Filament lamp: gradient falls, resistance rises (hotter, more lattice vibrations)
  • NTC thermistor: gradient rises, resistance falls (more conduction electrons)
  • Diode: conducts forward above about 0.6 V, negligible current in reverse
  • Resistance on a curve is V/I at that point

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Electrical power and I-V characteristics

  1. An electric kettle is rated 2.3 kW when connected to the 230 V mains supply. Its heating element is a single piece of resistance wire.
    The kettle is switched on for 3.0 minutes at its rated power. Calculate the energy transferred by the element. Give your answer in joules.2 marks
  2. A student investigates a filament lamp using a variable power supply. At a p.d. of 2.0 V the current in the lamp is 0.50 A, and at a p.d. of 12 V the current is 1.5 A.
    Explain why the resistance of the lamp at 12 V is greater than its resistance at 2.0 V.2 marks
  3. A silicon diode is connected in series with a 220 Ω resistor and a 6.0 V battery of negligible internal resistance. When the diode is forward-biased the p.d. across it is 0.70 V.
    Calculate the current in the circuit.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).