Refraction and total internal reflectionEdexcel A-Level Physics: Revision notes
Section 1
Refractive index
Refraction is the change in direction of a wave when it crosses a boundary between media because its speed changes. The refractive index n of a medium measures how much it slows light:
n = c/v
where c is the speed of light in a vacuum (3.00 × 10⁸ m s⁻¹, and almost the same in air) and v is the speed in the medium. Since v < c, n is always greater than 1 (air is about 1.00, water 1.33, glass about 1.5). A medium with a higher n is optically denser.
When light enters a denser medium it slows down and its wavelength shortens, but its frequency is unchanged.
Section 2
Snell's law
At a boundary between medium 1 and medium 2:
n₁ sin θ₁ = n₂ sin θ₂
where the angles are measured from the normal. Entering a denser medium the ray bends towards the normal, and leaving it the ray bends away from the normal. A ray along the normal (θ = 0) passes straight through.
From n = c/v it follows that n₁/n₂ = v₂/v₁ = λ₂/λ₁.
Measure angles from the normal, not from the surface of the block.
Section 3
Critical angle and total internal reflection
When light travels from a denser to a less dense medium, the refracted ray bends away from the normal. As the angle of incidence rises, the angle of refraction reaches 90° at the critical angle C. At larger angles there is no refracted ray and all of the light is reflected: total internal reflection (TIR).
Putting θ₂ = 90° into Snell's law for a boundary with air:
sin C = 1/n
For glass of n = 1.50, C = 42°. For water (n = 1.33), C = 49°. For diamond (n = 2.42), C = 24°.
A higher refractive index gives a smaller critical angle. In general, sin C = n₂/n₁ between two media.
Section 4
Predicting total internal reflection
Two conditions must both be met for TIR:
- The light is travelling towards a medium of lower refractive index (e.g. glass to air).
- The angle of incidence is greater than the critical angle.
To predict what happens, calculate C and compare it with the angle of incidence. Below C, most of the light is refracted (with some partial reflection). Above C, TIR occurs.
Uses: optical fibres carry light by repeated TIR in a core with a cladding of lower n, and cut diamonds sparkle because the small critical angle gives much TIR inside the stone.
Section 5
Core practical: refractive index of a solid
Use a rectangular glass block, a ray box with a single slit, a protractor and paper.
- Draw round the block and draw a normal at the point where the ray enters.
- Direct a narrow ray along lines at different angles of incidence (about 10° to 70°) and mark the ray with dots well apart on each side.
- Join the dots to find the ray inside the block and measure θ₁ and θ₂ from the normal.
- Plot sin θ₁ against sin θ₂. The graph is a straight line through the origin whose gradient is n.
Using a graph reduces random error and shows up anomalies.
Section 6
Worked example
A ray in air hits glass (n = 1.50) at 40°.
sin θ₂ = sin 40° ÷ 1.50 = 0.429, so θ₂ = 25°
Speed in glass: v = c/n = 3.00 × 10⁸ ÷ 1.50 = 2.0 × 10⁸ m s⁻¹
Critical angle for glass to air: sin C = 1/1.50, so C = 42°. A ray inside the glass hitting the surface at 50° is totally internally reflected, because 50° is greater than 42°.
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Refraction and total internal reflection
- A ray of light in air strikes the flat surface of a glass block of refractive index 1.50 at an angle of incidence of 40°. The speed of light in air is 3.00 × 10⁸ m s⁻¹ and the refractive index of air may be taken as 1.00.Calculate the angle of refraction of the ray inside the glass.2 marks
- A lamp at the bottom of a swimming pool shines light upwards on to the surface of the water. The refractive index of water is 1.33 and that of air is 1.00.Calculate the angle between the normal and the refracted ray in the air for the ray in (b).2 marks
- A student determines the refractive index of a rectangular glass block. She uses a ray box with a single slit to direct a narrow ray of light on to the block, and measures the angle of incidence θ₁ in air and the angle of refraction θ₂ inside the block for several different rays. She plots sin θ₁ against sin θ₂ and obtains a straight line through the origin with a gradient of 1.52.Explain why the graph is a straight line through the origin with a gradient equal to the refractive index of the glass, and calculate the speed of light in the block.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).