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Forces, Newton's laws and free-body diagramsEdexcel A-Level Physics: Revision notes

Section 1

Free-body diagrams

A free-body diagram shows a single object (a particle or rigid body) drawn separately, with only the forces acting on it shown as labelled arrows from the object, drawn along the line of action and with length roughly proportional to size. Never include forces the object exerts on other things.

Common forces: weight W (downwards, from the gravitational field), normal contact force N (perpendicular to a surface), friction F (along a surface, opposing sliding), tension T (along a string), drag or air resistance (opposing motion) and upthrust. Resolve forces that are at an angle into perpendicular components; the resultant is found by adding components in each direction.

Key termsfree-body diagramresultant force
Common mistake

Drawing a 'force of motion' or 'force of inertia' in the direction of movement. Objects do not need a forward force to keep moving at constant velocity.

Section 2

Newton's first and second laws

First law: an object remains at rest or moves at constant velocity unless a resultant force acts on it. Second law: the resultant force on an object equals the rate of change of its momentum; for constant mass this is F = ma, with the acceleration in the direction of the resultant force.

For equilibrium the resultant force is zero (a = 0), but the object may still be moving at constant velocity. To use F = ma, find the resultant, then divide by the mass. The newton is the force which gives a mass of 1 kg an acceleration of 1 m s⁻².

Worked example. A 1200 kg car with driving force 3600 N and resistive forces 600 N: F = 3600 − 600 = 3000 N, so a = 3000/1200 = 2.5 m s⁻².

Key termsNewton's first lawNewton's second lawF = ma
Exam tip

Always find the resultant force first. Use the mass of everything that accelerates together.

Section 3

Weight and gravitational field strength

Weight W is the force on a mass due to a gravitational field: W = mg, where g is the gravitational field strength. Using g = F/m, g is the force per unit mass, measured in N kg⁻¹ (the same as m s⁻² for free fall). Near the Earth's surface g ≈ 9.81 N kg⁻¹.

Mass is the amount of matter (kg) and does not change with location; weight is a force (N) and does. In a lift accelerating upwards, a passenger feels a contact force N = m(g + a), which is why apparent weight changes while true weight does not.

Key termsweightgravitational field strength

Section 4

Terminal velocity

When an object falls through a fluid, the drag force increases with speed. At first the weight exceeds the drag, so the object accelerates downwards. As speed increases, drag increases, so the resultant force and acceleration fall. When drag equals weight (plus upthrust if relevant) the resultant force is zero and the object falls at constant terminal velocity.

On a velocity–time graph the curve flattens to a horizontal line. If a parachute opens, drag suddenly exceeds weight, the object decelerates, and a new, smaller terminal velocity is reached. Initially, at the start of the fall, drag is zero and a = g.

Key termsterminal velocitydrag

Section 5

Newton's third law and interaction pairs

Third law: when object A exerts a force on object B, B exerts an equal and opposite force on A. The two forces of an interaction pair are always: the same type of force (both gravitational, both contact, and so on), equal in magnitude, opposite in direction, and acting on different objects.

Example: a book resting on a table. The weight of the book (Earth pulling the book) pairs with the book's gravitational pull on the Earth. The contact force of the table on the book pairs with the contact force of the book on the table. The weight and the table's contact force are equal and opposite but are not an interaction pair, because they act on the same object and are different types.

Key termsinteraction pairNewton's third law
Common mistake

Saying the weight and the normal contact force on a book are a third law pair. They act on the same object, so they cannot be.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Forces, Newton's laws and free-body diagrams

  1. A book of mass 0.80 kg rests on a horizontal table.
    Calculate the weight of the book and explain, using Newton's first law, why the contact force from the table has this same size.2 marks
  2. A car of mass 1200 kg accelerates in a straight line from rest along a level road. Its engine produces a driving force of 3600 N and the resistive forces on the car total 600 N.
    At a higher speed the resistive forces rise to 3600 N while the driving force is unchanged. Describe and explain the motion of the car from this point.2 marks
  3. A skydiver of mass 80 kg falls vertically with her parachute closed. At one instant her speed is 30 m s⁻¹ and the air resistance on her is 360 N.
    Calculate the acceleration of the skydiver at this instant.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).