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Second-order recurrence relationsEdexcel A-Level Further Maths: Flashcards

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What is a second-order linear recurrence relation?

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What is a second-order linear recurrence relation?
One linking un+2u_{n+2}, un+1u_{n+1} and unu_n with constant coefficients.
How many initial conditions are needed?
Two, for example u1u_1 and u2u_2.
What is the auxiliary equation of p un+2+q un+1+r un=0p\,u_{n+2}+q\,u_{n+1}+r\,u_n=0?
p m2+q m+r=0p\,m^2+q\,m+r=0.
Complementary function for distinct real roots m1,m2m_1,m_2?
A m1n+B m2nA\,m_1^n+B\,m_2^n.
Complementary function for a repeated root mm?
(A+Bn) mn(A+Bn)\,m^n.
How do you find the particular solution for a constant right-hand side?
Substitute un=λu_n=\lambda into all terms and solve for λ\lambda.
What is the general solution of the non-homogeneous relation?
Complementary function plus particular solution.
How do you find AA and BB?
Put the two initial conditions into the general solution and solve simultaneously.
Roots of 2m2+7m−15=02m^2+7m-15=0?
m=32m=\frac32 and m=−5m=-5.
Solve 2un+2+7un+1−15un=62u_{n+2}+7u_{n+1}-15u_n=6 with u1=10u_1=10, u2=−17u_2=-17.
un=4(32)n−(−5)n−1u_n=4\left(\frac32\right)^n-(-5)^n-1.
What does unu_n approach if all roots satisfy ∣m∣<1|m|<1?
The particular solution λ\lambda.
How can you check your formula?
Find u3u_3 from the recurrence and from the formula; they must agree.

Exam questions on Second-order recurrence relations

  1. A sequence satisfies un+2=5un+1−6unu_{n+2}=5u_{n+1}-6u_n with u1=5u_1=5 and u2=13u_2=13.
    Find unu_n in terms of nn.2 marks
  2. A sequence satisfies un+2=6un+1−9unu_{n+2}=6u_{n+1}-9u_n with u1=3u_1=3 and u2=18u_2=18.
    Find unu_n in terms of nn.2 marks
  3. A sequence satisfies un+2−un+1−6un=12u_{n+2}-u_{n+1}-6u_n=12 with u1=2u_1=2 and u2=20u_2=20.
    Find the complementary function and a particular solution of the form un=λu_n=\lambda.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).