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Division theorem, Euclidean algorithm and Bezout's identityEdexcel A-Level Further Maths: Flashcards

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State the division theorem.

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State the division theorem.
For b>0b>0, a=bq+ra=bq+r with unique integers q,rq,r and 0≤r<b0\leq r<b.
What is the key fact behind the Euclidean algorithm?
hcf(a,b)=hcf(b,r)\text{hcf}(a,b)=\text{hcf}(b,r) where a=bq+ra=bq+r.
How does the Euclidean algorithm give the hcf?
Repeat a=bq+ra=bq+r on divisor and remainder; the last non-zero remainder is the hcf.
What does coprime mean?
The hcf of the two integers is 11.
Formula for the lcm using the hcf?
lcm(a,b)=abhcf(a,b)\text{lcm}(a,b)=\frac{ab}{\text{hcf}(a,b)}.
State Bezout's identity.
There are integers x,yx,y with ax+by=hcf(a,b)ax+by=\text{hcf}(a,b).
How do you find xx and yy in Bezout's identity?
Back substitution: write each remainder as a−bqa-bq and work upwards from the hcf.
hcf and lcm of 252252 and 198198?
hcf 1818, lcm 27722772.
Bezout combination for 240240 and 4646?
2=47(46)−9(240)2=47(46)-9(240).
When does ax+by=cax+by=c have integer solutions?
If and only if hcf(a,b)\text{hcf}(a,b) divides cc.
Why has 1547x+504y=101547x+504y=10 no integer solutions?
The hcf is 77, so the left side is always a multiple of 77, and 7∤107\nmid10.
Write 252252 as 198q+r198q+r.
252=1×198+54252=1\times198+54.

Exam questions on Division theorem, Euclidean algorithm and Bezout's identity

  1. Consider the integers 252252 and 198198.
    Find the lowest common multiple of 252252 and 198198.2 marks
  2. A florist has 391 roses and 221 lilies. She makes identical bouquets, using every flower, with each bouquet containing the same number of roses and the same number of lilies.
    Explain why hcf(391,221)=hcf(221,170)\text{hcf}(391,221)=\text{hcf}(221,170).2 marks
  3. Let a=240a=240 and b=46b=46.
    Use the Euclidean algorithm to find the highest common factor of aa and bb.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).