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Rational expressionsEdexcel A-Level Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Maths

Rational expressions

Total 27 marks

Name

Class

Date

  1. 1
    The expression x2−9x2+x−6\frac{x^2-9}{x^2+x-6} is defined for all real xx except where the denominator is zero.
    (a)
    Which expression is equal to x2−9x2+x−6\frac{x^2-9}{x^2+x-6} for values of xx where it is defined?
    [1 mark]
    • Ax−3x+2\frac{x-3}{x+2}
    • Bx+3x−2\frac{x+3}{x-2}
    • C−9x−6\frac{-9}{x-6}
    • Dx−3x−2\frac{x-3}{x-2}
    (b)
    For which values of xx is the original expression x2−9x2+x−6\frac{x^2-9}{x^2+x-6} undefined?
    [1 mark]
    • Ax=−3x=-3 and x=2x=2
    • Bx=2x=2 only
    • Cx=3x=3 and x=−3x=-3
    • Dx=−3x=-3 only
    (c)
    Hence write x2−9x2+x−6\frac{x^2-9}{x^2+x-6} in the form A+Bx−2A+\frac{B}{x-2}, where AA and BB are constants.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The expression x3+8x2−4\frac{x^3+8}{x^2-4} is considered for values of xx where it is defined.
    (a)
    Which expression is equal to x3+8x2−4\frac{x^3+8}{x^2-4}?
    [1 mark]
    • Ax+2x−2\frac{x+2}{x-2}
    • Bx2+4x−2\frac{x^2+4}{x-2}
    • Cx2−2x+4x−2\frac{x^2-2x+4}{x-2}
    • Dx2+2x+4x−2\frac{x^2+2x+4}{x-2}
    (b)
    What is the value of x3+8x2−4\frac{x^3+8}{x^2-4} when x=3x=3?
    [1 mark]
    • A55
    • B77
    • C3535
    • D3513\frac{35}{13}
    (c)
    Hence write x3+8x2−4\frac{x^3+8}{x^2-4} in the form x+kx−2x+\frac{k}{x-2}, where kk is a constant.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The function f(x)=3x2+x−22x2−x−3f(x)=\frac{3x^2+x-2}{2x^2-x-3} is defined for all real xx except where its denominator is zero.
    (a)
    Simplify f(x)f(x).
    [3 marks]
    (b)
    Hence solve f(x)=2f(x)=2, and write f(x)f(x) in the form p+q2x−3p+\frac{q}{2x-3}, where pp and qq are constants.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Let A=x2−5x+6x2−4A=\frac{x^2-5x+6}{x^2-4} and B=x2+5x+6x2+4x+3B=\frac{x^2+5x+6}{x^2+4x+3}.
    (a)
    (i) Simplify AA.
    (ii) Simplify
    BB.
    (iii) Hence show that
    A×B=x−3x+1A\times B=\frac{x-3}{x+1}.
    [6 marks]
    (b)
    Let E=A×B=x−3x+1E=A\times B=\frac{x-3}{x+1}.
    (i) Write
    EE in the form 1+kx+11+\frac{k}{x+1}.
    (ii) Solve
    E=12E=\frac12.
    (iii) Explain why
    EE can never equal 11.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).