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Forces and Newton's first lawEdexcel A-Level Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Maths

Forces and Newton's first law

Total 27 marks

Name

Class

Date

  1. 1
    A box of weight 200200 N rests on a rough horizontal floor. A horizontal force of 3535 N pushes on the box, but the box does not move. Model the box as a particle.
    (a)
    Find the magnitude of the normal reaction of the floor on the box.
    [1 mark]
    • A3535 N
    • B165165 N
    • C235235 N
    • D200200 N
    (b)
    Which statement about the friction (resistance) force on the box is correct?
    [1 mark]
    • AIt is 3535 N and acts in the direction opposite to the push.
    • BIt is 3535 N and acts in the same direction as the push.
    • CIt is zero, because the box is not moving.
    • DIt is 200200 N and acts in the direction opposite to the push.
    (c)
    The push is increased to 6060 N and the box now moves along the floor at a constant speed. State the magnitude of the resistance to the box's motion and justify your answer.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A car travels along a straight horizontal road at a constant speed of 2525 m s−1^{-1}. The engine provides a driving force of 18001800 N. Model the car as a particle.
    (a)
    Which statement about the resistance to the car's motion is correct?
    [1 mark]
    • AIt is 00 N, because the car is not accelerating.
    • BIt is 18001800 N, equal to the driving force.
    • CIt is greater than 18001800 N, because the car is moving forwards.
    • DIt cannot be found without the mass of the car.
    (b)
    The driving force is increased to 24002400 N while the resistance stays the same. Which statement is correct?
    [1 mark]
    • AThe car continues at 2525 m s−1^{-1}, because the driving force is greater than the resistance.
    • BThe resultant force is 600600 N backwards, so the car slows down.
    • CThe resultant force is 600600 N forwards, so the car's velocity changes.
    • DThe resultant force is 42004200 N, because the forces add.
    (c)
    Explain why the engine must provide a driving force even though the car is moving at constant speed.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Three horizontal forces act on a particle: F1=(3i+5j)\mathbf{F}_1=(3\mathbf{i}+5\mathbf{j}) N, F2=(−7i+2j)\mathbf{F}_2=(-7\mathbf{i}+2\mathbf{j}) N and F3=(pi+qj)\mathbf{F}_3=(p\mathbf{i}+q\mathbf{j}) N, where i\mathbf{i} and j\mathbf{j} are perpendicular unit vectors. The particle moves with constant velocity.
    (a)
    Find the values of pp and qq.
    [3 marks]
    (b)
    Find the magnitude of F3\mathbf{F}_3, and the acute angle between the line of action of F3\mathbf{F}_3 and the direction of i\mathbf{i}.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A skydiver of weight 850850 N is modelled as a particle. Air resistance acts on the skydiver while falling.
    (a)
    (i) With its parachute open, the skydiver falls vertically at a constant speed of 55 m s−1^{-1}. State the two forces acting and find the air resistance.
    (ii) After landing, the skydiver stands at rest on horizontal ground while a steady horizontal wind drags the parachute with a horizontal force of
    4040 N. Find the normal reaction of the ground and the friction force, stating the direction of each.
    [6 marks]
    (b)
    The skydiver leaves the aircraft with zero speed, with the parachute closed. Air resistance increases as the speed increases. Using Newton's first law, explain how the motion changes until a constant speed is reached before the parachute opens. A student claims that, to keep falling at constant speed, there must be a downward resultant force. Explain whether the claim is correct.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).