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Compound and double angle formulaeEdexcel A-Level Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Maths

Compound and double angle formulae

Total 27 marks

Name

Class

Date

  1. 1
    Angles AA and BB are acute, with sin⁡A=35\sin A=\frac{3}{5} and cos⁡B=513\cos B=\frac{5}{13}.
    (a)
    Find the value of sin⁡(A+B)\sin(A+B).
    [1 mark]
    • A5665\frac{56}{65}
    • B−3365-\frac{33}{65}
    • C6365\frac{63}{65}
    • D313\frac{3}{13}
    (b)
    Find the value of cos⁡(A+B)\cos(A+B).
    [1 mark]
    • A1665\frac{16}{65}
    • B−1665-\frac{16}{65}
    • C5665\frac{56}{65}
    • D413\frac{4}{13}
    (c)
    Find the exact value of tan⁡(A+B)\tan(A+B).
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The angle xx is acute and tan⁡x=34\tan x=\frac{3}{4}.
    (a)
    Find the value of tan⁡2x\tan2x.
    [1 mark]
    • A2425\frac{24}{25}
    • B725\frac{7}{25}
    • C32\frac{3}{2}
    • D247\frac{24}{7}
    (b)
    Find the value of cos⁡2x\cos2x.
    [1 mark]
    • A725\frac{7}{25}
    • B2425\frac{24}{25}
    • C1825\frac{18}{25}
    • D−725-\frac{7}{25}
    (c)
    Hence find the exact value of cos⁡4x\cos4x.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Consider the equation cos⁡2θ+3sin⁡θ=2\cos2\theta+3\sin\theta=2, where 0≤θ<360∘0\le\theta<360^\circ.
    (a)
    Show that the equation can be written as 2sin⁡2θ−3sin⁡θ+1=02\sin^2\theta-3\sin\theta+1=0.
    [3 marks]
    (b)
    Hence solve the equation, giving all solutions in the interval 0≤θ<360∘0\le\theta<360^\circ.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Let f(θ)=3cos⁡θ+sin⁡θf(\theta)=\sqrt3\cos\theta+\sin\theta, where θ\theta is measured in degrees.
    (a)
    (i) Write f(θ)f(\theta) in the form Rcos⁡(θ−α)R\cos(\theta-\alpha), where R>0R>0 and 0<α<90∘0<\alpha<90^\circ.
    (ii) Hence solve
    f(θ)=1f(\theta)=1 for 0≤θ<360∘0\le\theta<360^\circ.
    [6 marks]
    (b)
    (i) Write down the maximum value of f(θ)f(\theta) and the smallest positive value of θ\theta at which it occurs.
    (ii) Solve
    f(θ)=2f(\theta)=\sqrt2 for 0≤θ<360∘0\le\theta<360^\circ.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).