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The modulus functionEdexcel A-Level Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Maths

The modulus function

Total 27 marks

Name

Class

Date

  1. 1
    The function ff is defined by f(x)=∣2x−1∣f(x)=|2x-1|.
    (a)
    What is the value of f(−2)f(-2)?
    [1 mark]
    • A−5-5
    • B55
    • C33
    • D−3-3
    (b)
    What are the coordinates of the vertex of the graph of y=∣2x−1∣y=|2x-1|?
    [1 mark]
    • A(−12,0)\left(-\frac12,0\right)
    • B(0,1)(0,1)
    • C(12,0)\left(\frac12,0\right)
    • D(12,1)\left(\frac12,1\right)
    (c)
    Solve f(x)=3f(x)=3.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The function gg is defined by g(x)=∣3x+2∣g(x)=|3x+2|.
    (a)
    Which set of values of xx satisfies g(x)<4g(x)<4?
    [1 mark]
    • Ax<−2x<-2 or x>23x>\frac23
    • B−23<x<2-\frac23<x<2
    • C−43<x<43-\frac43<x<\frac43
    • D−2<x<23-2<x<\frac23
    (b)
    Which set of values of xx satisfies g(x)>4g(x)>4?
    [1 mark]
    • Ax<−2x<-2 or x>23x>\frac23
    • B−2<x<23-2<x<\frac23
    • Cx<−2x<-2 and x>23x>\frac23
    • Dx>23x>\frac23
    (c)
    State the coordinates where the graph of y=g(x)y=g(x) meets the yy-axis, and the coordinates of its vertex.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Consider the graph of y=∣2x−1∣y=|2x-1| and the straight line y=xy=x.
    (a)
    Solve ∣2x−1∣=x|2x-1|=x.
    [3 marks]
    (b)
    Hence solve ∣2x−1∣>x|2x-1|>x.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Let f(x)=∣3x−6∣f(x)=|3x-6|, and let LkL_k be the line y=x+ky=x+k, where kk is a constant.
    (a)
    In this part take k=2k=2, so the line is y=x+2y=x+2.
    (i) State the coordinates of the points where the graph of
    y=f(x)y=f(x) meets the axes.
    (ii) Solve
    ∣3x−6∣=x+2|3x-6|=x+2.
    (iii) Hence solve
    ∣3x−6∣<x+2|3x-6|<x+2.
    [6 marks]
    (b)
    (i) Show that the solutions of ∣3x−6∣=x+k|3x-6|=x+k, where they exist, are x=k+62x=\frac{k+6}{2} and x=6−k4x=\frac{6-k}{4}.
    (ii) The vertex of the graph of
    y=f(x)y=f(x) is at (2,0)(2,0). Use this to find the set of values of kk for which the equation ∣3x−6∣=x+k|3x-6|=x+k has two solutions.
    (iii) Find the value of
    kk for which the equation has exactly one solution, and state that solution.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).