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Reciprocal and inverse trigonometric functionsEdexcel A-Level Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Maths

Reciprocal and inverse trigonometric functions

Total 27 marks

Name

Class

Date

  1. 1
    The angle θ\theta is acute and tan⁡θ=512\tan\theta=\frac{5}{12}.
    (a)
    Find the value of sec⁡θ\sec\theta.
    [1 mark]
    • A1213\frac{12}{13}
    • B135\frac{13}{5}
    • C1312\frac{13}{12}
    • D125\frac{12}{5}
    (b)
    Find the value of cosec θ\mathrm{cosec}\,\theta.
    [1 mark]
    • A513\frac{5}{13}
    • B135\frac{13}{5}
    • C1312\frac{13}{12}
    • D125\frac{12}{5}
    (c)
    Use the identity cosec2θ=1+cot⁡2θ\mathrm{cosec}^2\theta=1+\cot^2\theta to confirm your value of cosec θ\mathrm{cosec}\,\theta.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The inverse trigonometric functions arcsin⁡\arcsin, arccos⁡\arccos and arctan⁡\arctan are defined using their principal values, with angles in radians.
    (a)
    State the domain and range of y=arcsin⁡xy=\arcsin x.
    [1 mark]
    • ADomain −π2≤x≤π2-\frac{\pi}{2}\le x\le\frac{\pi}{2}; range −1≤y≤1-1\le y\le1
    • BDomain −1≤x≤1-1\le x\le1; range 0≤y≤π0\le y\le\pi
    • CDomain all real xx; range −π2<y<π2-\frac{\pi}{2}<y<\frac{\pi}{2}
    • DDomain −1≤x≤1-1\le x\le1; range −π2≤y≤π2-\frac{\pi}{2}\le y\le\frac{\pi}{2}
    (b)
    Find the exact value of arccos⁡(−12)\arccos\left(-\frac12\right).
    [1 mark]
    • A2π3\frac{2\pi}{3}
    • Bπ3\frac{\pi}{3}
    • C−π3-\frac{\pi}{3}
    • D4π3\frac{4\pi}{3}
    (c)
    Find the exact value of arcsin⁡(sin⁡5π6)\arcsin\left(\sin\frac{5\pi}{6}\right), explaining why it is not 5π6\frac{5\pi}{6}.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    In this question 0≤θ<360∘0\le\theta<360^\circ.
    (a)
    Solve cosecθ2=2\mathrm{cosec}\frac{\theta}{2}=2.
    [3 marks]
    (b)
    Solve tan⁡2θ+sec⁡θ=1\tan^2\theta+\sec\theta=1.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    In this question you may use the identities sec⁡2θ≡1+tan⁡2θ\sec^2\theta\equiv1+\tan^2\theta and cosec2θ≡1+cot⁡2θ\mathrm{cosec}^2\theta\equiv1+\cot^2\theta.
    (a)
    (i) Prove that cot⁡θ+tan⁡θ≡sec⁡θ cosec θ\cot\theta+\tan\theta\equiv\sec\theta\,\mathrm{cosec}\,\theta.
    (ii) Prove that
    11−sin⁡θ+11+sin⁡θ≡2sec⁡2θ\frac{1}{1-\sin\theta}+\frac{1}{1+\sin\theta}\equiv2\sec^2\theta.
    [6 marks]
    (b)
    Solve cot⁡2x+cosec x=5\cot^2x+\mathrm{cosec}\,x=5 for 0≤x<2π0\le x<2\pi, giving non-exact answers to 3 significant figures.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).