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Solving trigonometric equationsEdexcel A-Level Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Maths

Solving trigonometric equations

Total 27 marks

Name

Class

Date

  1. 1
    The equation sin⁡(x+70∘)=0.5\sin(x+70^\circ)=0.5 is to be solved for 0<x<360∘0<x<360^\circ.
    (a)
    A calculator gives sin⁡−10.5=30∘\sin^{-1}0.5=30^\circ. What is the other value of x+70∘x+70^\circ between 0∘0^\circ and 360∘360^\circ?
    [1 mark]
    • A150∘150^\circ
    • B330∘330^\circ
    • C210∘210^\circ
    • D120∘120^\circ
    (b)
    Which pair gives all the solutions for xx?
    [1 mark]
    • A−40∘-40^\circ and 80∘80^\circ
    • B30∘30^\circ and 150∘150^\circ
    • C80∘80^\circ and 330∘330^\circ
    • D80∘80^\circ and 320∘320^\circ
    (c)
    Solve sin⁡(x+70∘)=−0.5\sin(x+70^\circ)=-0.5 for 0<x<360∘0<x<360^\circ.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The equation 3+5cos⁡2x=13+5\cos2x=1 is to be solved for −180∘<x<180∘-180^\circ<x<180^\circ.
    (a)
    Which is the correct rearrangement of the equation?
    [1 mark]
    • Acos⁡2x=25\cos2x=\frac25
    • Bcos⁡2x=−25\cos2x=-\frac25
    • Ccos⁡2x=−2\cos2x=-2
    • Dcos⁡x=−15\cos x=-\frac15
    (b)
    Which interval must be used when solving for 2x2x?
    [1 mark]
    • A−180∘<2x<180∘-180^\circ<2x<180^\circ
    • B0∘<2x<360∘0^\circ<2x<360^\circ
    • C−360∘<2x<360∘-360^\circ<2x<360^\circ
    • D−90∘<2x<90∘-90^\circ<2x<90^\circ
    (c)
    Solve the equation, giving your answers to 1 decimal place.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Consider the equation 6cos⁡2x+sin⁡x−5=06\cos^2x+\sin x-5=0 for 0≤x<360∘0\le x<360^\circ.
    (a)
    Show that the equation can be written as 6sin⁡2x−sin⁡x−1=06\sin^2x-\sin x-1=0.
    [3 marks]
    (b)
    Hence solve the equation for 0≤x<360∘0\le x<360^\circ, giving answers to 1 decimal place where necessary.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    In this question xx is measured in radians with 0≤x<2π0\le x<2\pi, and answers should be given as exact multiples of π\pi.
    (a)
    Solve 2cos⁡2x=3−3sin⁡x2\cos^2x=3-3\sin x.
    [6 marks]
    (b)
    Solve sin⁡3x=32\sin3x=\frac{\sqrt3}{2}.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).