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Integration as the reverse of differentiationEdexcel A-Level Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Maths

Integration as the reverse of differentiation

Total 27 marks

Name

Class

Date

  1. 1
    A curve has gradient function dydx=6x2−4x+5\frac{dy}{dx}=6x^{2}-4x+5 and passes through the point (1,7)(1,7).
    (a)
    Find ∫(6x2−4x+5)dx\int\left(6x^{2}-4x+5\right)dx.
    [1 mark]
    • A12x−412x-4
    • B6x3−4x2+5x+c6x^{3}-4x^{2}+5x+c
    • C2x3−2x2+5x+c2x^{3}-2x^{2}+5x+c
    • D2x3−2x2+5x2x^{3}-2x^{2}+5x
    (b)
    Find the value of the constant of integration for the curve.
    [1 mark]
    • A77
    • B−2-2
    • C1212
    • D22
    (c)
    Find the yy-coordinate of the point on the curve where x=2x=2.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A curve y=f(x)y=f(x), for x>0x>0, has gradient function f′(x)=(x−1)2xf'(x)=\frac{(x-1)^{2}}{\sqrt x} and passes through the point (1,2)(1,2).
    (a)
    Which expression is equal to (x−1)2x\frac{(x-1)^{2}}{\sqrt x}?
    [1 mark]
    • Ax3/2−2x1/2+x−1/2x^{3/2}-2x^{1/2}+x^{-1/2}
    • Bx3/2−x−1/2x^{3/2}-x^{-1/2}
    • Cx5/2−2x3/2+x1/2x^{5/2}-2x^{3/2}+x^{1/2}
    • Dx3/2−2x1/2−x−1/2x^{3/2}-2x^{1/2}-x^{-1/2}
    (b)
    Find ∫(x−1)2x dx\int\frac{(x-1)^{2}}{\sqrt x}\,dx.
    [1 mark]
    • A32x1/2−x−1/2−12x−3/2+c\frac32x^{1/2}-x^{-1/2}-\frac12x^{-3/2}+c
    • B25x5/2−43x3/2+2x1/2+c\frac25x^{5/2}-\frac43x^{3/2}+2x^{1/2}+c
    • C25x5/2−43x3/2+12x1/2+c\frac25x^{5/2}-\frac43x^{3/2}+\frac12x^{1/2}+c
    • D25x5/2−43x3/2+2x−1/2+c\frac25x^{5/2}-\frac43x^{3/2}+2x^{-1/2}+c
    (c)
    Find an equation of the curve.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A curve y=f(x)y=f(x), for x>0x>0, has gradient function f′(x)=3x2−6x3f'(x)=3x^{2}-\frac{6}{x^{3}} and passes through the point (1,2)(1,2).
    (a)
    Find f(x)f(x).
    [3 marks]
    (b)
    Find an equation of the tangent to the curve at the point where x=2x=2, in the form y=mx+cy=mx+c.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A curve CC, defined for x<0x<0, has gradient function dydx=(x+2)2x4\frac{dy}{dx}=\frac{(x+2)^{2}}{x^{4}} and passes through the point (−1,1)(-1,1).
    (a)
    Find yy in terms of xx.
    [6 marks]
    (b)
    Find the coordinates of the stationary point of CC, and deduce that it is neither a maximum nor a minimum.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).