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Damped oscillationsAQA A-Level Further Maths: Revision notes

Section 1

Modelling damped motion

Real oscillations lose energy to resistance. In the simplest model the damping force is proportional to the velocity and opposes it, so for a particle of mass mm with restoring force kxkx and resistance cx′cx': mx′′=−kx−cx′.mx''=-kx-cx'. Dividing by mm gives a second order equation of the form x′′+2px′+qx=0x''+2px'+qx=0 with p,q>0p,q>0. The x′x' term is the damping: if it is absent the motion is simple harmonic. The type of motion depends on the roots of the auxiliary equation m2+2pm+q=0m^2+2pm+q=0, that is m=−p±p2−qm=-p\pm\sqrt{p^2-q}, and so on the sign of p2−qp^2-q (equivalently the discriminant of the auxiliary equation).

Key termsdamping forceauxiliary equation
Common mistake

Forgetting to divide every term by mm. For mass 0.5 kg the coefficients double.

Section 2

Light damping

If p2<qp^2<q the roots are complex, m=−p±iβm=-p\pm i\beta with β=q−p2\beta=\sqrt{q-p^2}, and x=e−pt(Acos⁡βt+Bsin⁡βt).x=e^{-pt}(A\cos\beta t+B\sin\beta t). This is an oscillation whose amplitude decays like e−pte^{-pt}. The particle passes through OO repeatedly, with the time between successive passes in the same direction equal to 2πβ\frac{2\pi}{\beta}. This is longer than the undamped period 2πq\frac{2\pi}{\sqrt q}, because the damping slows the motion. Light damping occurs when the resistance is small compared with the restoring force.

Key termslight damping
Exam tip

The real part of the complex root gives the decay rate e−pte^{-pt}. The imaginary part gives the oscillation frequency.

Section 3

Critical damping

If p2=qp^2=q there is one repeated real root m=−pm=-p, and x=(A+Bt)e−pt.x=(A+Bt)e^{-pt}. This is the borderline case: the particle returns to equilibrium as quickly as possible without oscillating (it can pass through OO at most once). Critical damping is used in car suspensions and door closers so that things settle fast and without bouncing.

Key termscritical damping
Common mistake

The repeated root gives (A+Bt)e−pt(A+Bt)e^{-pt}, not Ae−pt+Be−ptAe^{-pt}+Be^{-pt}, which has only one constant.

Section 4

Heavy damping

If p2>qp^2>q there are two distinct real roots m1,m2m_1,m_2, both negative, and x=Aem1t+Bem2t.x=Ae^{m_1t}+Be^{m_2t}. There is no oscillation. The particle creeps back to OO more slowly than with critical damping (it passes through OO at most once). Heavy damping occurs when the resistance is large, for example a door closing slowly in thick oil.

Key termsheavy damping

Section 5

Deciding the type and interpreting solutions

Find the discriminant of m2+2pm+q=0m^2+2pm+q=0, which is 4(p2−q)4(p^2-q):

  • negative: light (oscillates, decaying amplitude)
  • zero: critical (fastest return, no oscillation)
  • positive: heavy (slow return, no oscillation). Example. A 1 kg particle has restoring force 9x9x and resistance kvkv. Then x′′+kx′+9x=0x''+kx'+9x=0 and the discriminant is k2−36k^2-36. Critical damping needs k=6k=6; light damping needs 0<k<60<k<6; heavy damping needs k>6k>6. In every case the exponential factor forces x→0x\to0 as t→∞t\to\infty.
Exam tip

In an exam, name the type of damping and link it to the roots: complex roots means oscillation, a repeated root means critical, real distinct roots means heavy.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Damped oscillations

  1. A particle moves on a straight line, with displacement xx m from OO at time tt s, where x′′+6x′+25x=0x''+6x'+25x=0.
    Write down the general solution of the differential equation.2 marks
  2. A particle of mass 0.5 kg moves on a straight line, with displacement xx m from OO at time tt s. It is acted on by a restoring force of magnitude 2∣x∣2|x| N towards OO and a resistive force of magnitude λv\lambda v N, where vv m s−1^{-1} is its speed and λ\lambda is a positive constant.
    State, with a reason, the type of damping when λ=3\lambda=3.2 marks
  3. The displacement xx m of a particle from OO at time tt s satisfies x′′+4x′+4x=0x''+4x'+4x=0. When t=0t=0, x=3x=3 and x′=0x'=0.
    Show that the damping is critical and write down the general solution.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).