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De Moivre's theoremAQA A-Level Further Maths: Subtopic test

10 questions, 27 marks

AQA A-Level Further Maths

De Moivre's theorem

Total 27 marks

Name

Class

Date

  1. 1
    The complex number z=cos⁡π12+isin⁡π12z=\cos\frac{\pi}{12}+\mathrm{i}\sin\frac{\pi}{12}.
    (a)
    Find z4z^4.
    [1 mark]
    • A32+12i\frac{\sqrt3}{2}+\frac12\mathrm{i}
    • Bcos⁡π48+isin⁡π48\cos\frac{\pi}{48}+\mathrm{i}\sin\frac{\pi}{48}
    • C12+32i\frac12+\frac{\sqrt3}{2}\mathrm{i}
    • D4cos⁡π12+4isin⁡π124\cos\frac{\pi}{12}+4\mathrm{i}\sin\frac{\pi}{12}
    (b)
    Find z12z^{12}.
    [1 mark]
    • A11
    • B−1-1
    • Ci\mathrm{i}
    • D−i-\mathrm{i}
    (c)
    Express z−5z^{-5} in the form cos⁡α−isin⁡α\cos\alpha-\mathrm{i}\sin\alpha, stating the exact value of α\alpha.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The complex number w=1+iw=1+\mathrm{i}.
    (a)
    Write ww in modulus-argument form.
    [1 mark]
    • A2(cos⁡π4+isin⁡π4)\sqrt2\left(\cos\frac{\pi}{4}+\mathrm{i}\sin\frac{\pi}{4}\right)
    • B2(cos⁡π4+isin⁡π4)2\left(\cos\frac{\pi}{4}+\mathrm{i}\sin\frac{\pi}{4}\right)
    • C2(cos⁡π2+isin⁡π2)\sqrt2\left(\cos\frac{\pi}{2}+\mathrm{i}\sin\frac{\pi}{2}\right)
    • D2(cos⁡π4−isin⁡π4)\sqrt2\left(\cos\frac{\pi}{4}-\mathrm{i}\sin\frac{\pi}{4}\right)
    (b)
    Find w8w^8.
    [1 mark]
    • A256256
    • B16i16\mathrm{i}
    • C−16-16
    • D1616
    (c)
    Find w10w^{10} in the form a+bia+b\mathrm{i}.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The equation 8x3−6x−1=08x^3-6x-1=0 is to be solved.
    (a)
    Use de Moivre's theorem to show that cos⁡3θ=4cos⁡3θ−3cos⁡θ\cos3\theta=4\cos^3\theta-3\cos\theta.
    [3 marks]
    (b)
    By substituting x=cos⁡θx=\cos\theta, find the three roots of the equation in the form cos⁡(qπ)\cos(q\pi), where qq is a rational number.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    For real θ\theta, let C=∑k=0∞cos⁡kθ2kC=\displaystyle\sum_{k=0}^{\infty}\frac{\cos k\theta}{2^k} and S=∑k=0∞sin⁡kθ2kS=\displaystyle\sum_{k=0}^{\infty}\frac{\sin k\theta}{2^k}.
    (a)
    (i) By considering C+iSC+\mathrm{i}S as a geometric series, show that C+iS=22−cos⁡θ−isin⁡θC+\mathrm{i}S=\dfrac{2}{2-\cos\theta-\mathrm{i}\sin\theta}, explaining why the series converges.
    (ii) Hence show that
    C=4−2cos⁡θ5−4cos⁡θC=\dfrac{4-2\cos\theta}{5-4\cos\theta}.
    [6 marks]
    (b)
    (i) Find an expression for SS in terms of θ\theta.
    (ii) Show that
    C2+S2=45−4cos⁡θC^2+S^2=\dfrac{4}{5-4\cos\theta}, and hence find the greatest value of C2+S2C^2+S^2 as θ\theta varies.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).