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Induction for series and sequencesAQA A-Level Further Maths: Subtopic test

10 questions, 27 marks

AQA A-Level Further Maths

Induction for series and sequences

Total 27 marks

Name

Class

Date

  1. 1
    Let Sn=∑r=1nr(r+1)S_n=\sum_{r=1}^{n}r(r+1) for positive integers nn. A student is proving by induction that Sn=n(n+1)(n+2)3S_n=\frac{n(n+1)(n+2)}{3}.
    (a)
    Find the value of S4S_4.
    [1 mark]
    • A2020
    • B4040
    • C3030
    • D120120
    (b)
    Assume the result is true for n=kn=k. Which expression is Sk+1S_{k+1} before any simplification?
    [1 mark]
    • Ak(k+1)(k+2)3+(k+1)(k+2)\frac{k(k+1)(k+2)}{3}+(k+1)(k+2)
    • Bk(k+1)(k+2)3+k(k+1)\frac{k(k+1)(k+2)}{3}+k(k+1)
    • C(k+1)(k+2)(k+3)3+(k+1)(k+2)\frac{(k+1)(k+2)(k+3)}{3}+(k+1)(k+2)
    • Dk(k+1)(k+2)3+(k+1)\frac{k(k+1)(k+2)}{3}+(k+1)
    (c)
    Show that k(k+1)(k+2)3+(k+1)(k+2)=(k+1)(k+2)(k+3)3\frac{k(k+1)(k+2)}{3}+(k+1)(k+2)=\frac{(k+1)(k+2)(k+3)}{3}.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    For positive integers nn, let Tn=∑r=1n1r(r+1)T_n=\sum_{r=1}^{n}\frac{1}{r(r+1)}. It is to be proved by induction that Tn=nn+1T_n=\frac{n}{n+1}.
    (a)
    Find the value of T3T_3.
    [1 mark]
    • A1112\frac{11}{12}
    • B112\frac{1}{12}
    • C34\frac34
    • D43\frac43
    (b)
    Assume the result is true for n=kn=k. Which expression equals kk+1+1(k+1)(k+2)\frac{k}{k+1}+\frac{1}{(k+1)(k+2)}?
    [1 mark]
    • A1k+2\frac{1}{k+2}
    • Bk+2k+3\frac{k+2}{k+3}
    • Ck2+1(k+1)(k+2)\frac{k^2+1}{(k+1)(k+2)}
    • Dk+1k+2\frac{k+1}{k+2}
    (c)
    Write down the basis step for n=1n=1 and state the inductive hypothesis.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The sequence unu_n is defined by u1=3u_1=3 and un+1=3un−2u_{n+1}=3u_n-2 for n≥1n\ge1. A student suggests that un=2×3n−1+1u_n=2\times3^{n-1}+1.
    (a)
    Find u2u_2, u3u_3 and u4u_4, and show that the suggested formula gives the correct value of u4u_4.
    [3 marks]
    (b)
    Prove by induction that un=2×3n−1+1u_n=2\times3^{n-1}+1 for all positive integers nn.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    For positive integers nn, let An=∑r=1nr2A_n=\sum_{r=1}^{n}r^2 and Bn=∑r=1nr3B_n=\sum_{r=1}^{n}r^3.
    (a)
    Prove by induction that An=16n(n+1)(2n+1)A_n=\frac16n(n+1)(2n+1) for all positive integers nn.
    [6 marks]
    (b)
    Prove by induction that Bn=14n2(n+1)2B_n=\frac14n^2(n+1)^2 for all positive integers nn.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).