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Mean and variance, and link to Poisson processesAQA A-Level Further Maths: Subtopic test

10 questions, 27 marks

AQA A-Level Further Maths

Mean and variance, and link to Poisson processes

Total 27 marks

Name

Class

Date

  1. 1
    The lifetime, XX days, of a type of battery is modelled by an exponential distribution with parameter λ=0.05\lambda=0.05.
    (a)
    Find the mean lifetime of a battery.
    [1 mark]
    • A0.050.05 days
    • B2020 days
    • C400400 days
    • D0.00250.0025 days
    (b)
    Find the variance of the lifetime.
    [1 mark]
    • A400400
    • B2020
    • C0.00250.0025
    • D4040
    (c)
    Find the probability that a battery lasts longer than its mean lifetime.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Particles strike a detector at random, independently of each other, at a constant average rate of 12 per hour, so the number of strikes follows a Poisson process. Let TT minutes be the time between two successive strikes.
    (a)
    Which statement correctly describes TT?
    [1 mark]
    • ATT has a Poisson distribution with mean 12
    • BTT has an exponential distribution with mean 12 minutes
    • CTT has a normal distribution with mean 5 minutes
    • DTT has an exponential distribution with mean 5 minutes
    (b)
    Find the probability that the time between two successive strikes is more than 10 minutes.
    [1 mark]
    • A0.8650.865
    • B0.3680.368
    • C0.1350.135
    • D0.01830.0183
    (c)
    Find the standard deviation of TT in minutes.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The continuous random variable XX has an exponential distribution with parameter λ>0\lambda>0, so that f(x)=λe−λxf(x)=\lambda e^{-\lambda x} for x≥0x\ge0. You may use the fact that xe−λx→0xe^{-\lambda x}\to0 and x2e−λx→0x^2e^{-\lambda x}\to0 as x→∞x\to\infty.
    (a)
    Prove that E(X)=1λ\mathrm{E}(X)=\frac{1}{\lambda}.
    [3 marks]
    (b)
    Prove that Var(X)=1λ2\mathrm{Var}(X)=\frac{1}{\lambda^2}.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Faults occur at random, independently of each other, along a long cable at a constant average rate of 0.8 per kilometre, so the number of faults in a length of cable follows a Poisson process. The distance, XX km, between successive faults is modelled by an exponential distribution.
    (a)
    (i) State the distribution of XX, and find E(X)\mathrm{E}(X) and Var(X)\mathrm{Var}(X).
    (ii) Find the probability that the distance between two successive faults is greater than 2 km.

    (iii) Explain why your answer to (ii) is also the probability that a given 2 km length of cable contains no faults.
    [6 marks]
    (b)
    A technician inspects the cable from one end. The distance to the first fault is also exponential with the same parameter.
    (i) Find the probability that the first fault is between 1 km and 3 km from the end.

    (ii) Find the probability that there are exactly 2 faults in the first 3 km.

    (iii) The technician finds that faults are more common near the joints of the cable. Evaluate the effect on your answers to (i) and (ii).
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).