All flashcards topics

The forms R cos(theta ± a) and R sin(theta ± a)Edexcel International A Level Maths: Flashcards

What these 13 flashcards ask

  • What is the aim of writing a\cos\theta+b\sin\theta as R\cos(\theta\pm\alpha)?
  • Expand R\cos(\theta+\alpha).
  • Expand R\sin(\theta+\alpha).
  • Formula for R in a\cos\theta+b\sin\theta?
  • How do you find \alpha?
  • 3\sin\theta+4\cos\theta in the form R\sin(\theta+\alpha)?
  • Maximum value of R\sin(\theta+\alpha) and when it occurs?
  • Minimum value of R\cos(\theta+\alpha) and when it occurs?
  • Maximum of 5\cos\theta+12\sin\theta?
  • How many solutions has 5\cos\theta+12\sin\theta=14?
  • How do you solve a\cos\theta+b\sin\theta=c?
  • Why must the interval be shifted when solving R\cos(\theta+\alpha)=c?
  • Write \cos\theta-\sqrt3\sin\theta as R\cos(\theta+\alpha).

Exam questions on The forms R cos(theta ± a) and R sin(theta ± a)

  1. The expression 3sin⁡θ+4cos⁡θ3\sin\theta+4\cos\theta is written in the form Rsin⁡(θ+α)R\sin(\theta+\alpha), where R>0R>0 and 0<α<90∘0<\alpha<90^{\circ}.
    Hence state the maximum value of 3sin⁡θ+4cos⁡θ3\sin\theta+4\cos\theta and the smallest positive value of θ\theta at which it occurs, to 1 decimal place.2 marks
  2. Let f(θ)=cos⁡θ−3sin⁡θ\mathrm{f}(\theta)=\cos\theta-\sqrt3\sin\theta, with θ\theta in radians. It is written in the form Rcos⁡(θ+α)R\cos(\theta+\alpha), where R>0R>0 and 0<α<π20<\alpha<\frac{\pi}{2}.
    Hence find the minimum value of f(θ)\mathrm{f}(\theta) and the smallest positive value of θ\theta at which it occurs.2 marks
  3. Angles are measured in degrees and a calculator may be used.
    Express 5cos⁡θ−12sin⁡θ5\cos\theta-12\sin\theta in the form Rcos⁡(θ+α)R\cos(\theta+\alpha), where R>0R>0 and 0<α<90∘0<\alpha<90^{\circ}. Give α\alpha to 1 decimal place.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).