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Equilibrium of a particleEdexcel International A Level Maths: Flashcards

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Condition for a particle to be in equilibrium?

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Condition for a particle to be in equilibrium?
The resultant force is zero, so components sum to zero in every direction.
Formula for weight?
W=mgW=mg, with g=9.8g=9.8 m s−2^{-2}
Direction of the normal reaction?
Perpendicular to the surface, away from it.
What is a light string?
A string with negligible mass; the tension is the same throughout.
What is thrust?
The compressive force along a rod.
When does F=μRF=\mu R apply?
In limiting equilibrium, when the particle is on the point of slipping.
What is the general friction condition?
F≤μRF\le\mu R
Smooth slope at angle α\alpha: force PP up the slope holds weight WW. Find PP and RR.
P=Wsin⁡αP=W\sin\alpha, R=Wcos⁡αR=W\cos\alpha
Horizontal force HH holds weight WW on a smooth slope at α\alpha. Find HH.
H=Wtan⁡αH=W\tan\alpha
Effect on the normal reaction of pulling up at an angle?
It is reduced: R=W−Tsin⁡θR=W-T\sin\theta.
Effect on the normal reaction of pushing down at an angle?
It is increased: R=W+Psin⁡θR=W+P\sin\theta.
What do you do for a particle on two strings?
Resolve horizontally and vertically and solve the two equations simultaneously.

Exam questions on Equilibrium of a particle

  1. A crate of mass 20 kg rests on a rough horizontal floor. A rope attached to the crate is pulled with a force of 50 N at 30∘30^\circ above the horizontal, and the crate remains at rest. Take g=9.8g=9.8 m s−2^{-2} and model the crate as a particle.
    The crate is on the point of slipping. Find the coefficient of friction between the crate and the floor.2 marks
  2. A particle of weight 30 N is held in equilibrium on a smooth plane inclined at 30∘30^\circ to the horizontal by a force of magnitude PP N acting up the slope, parallel to the line of greatest slope.
    The force PP is removed and replaced by a horizontal force of magnitude HH N, so that the particle is still in equilibrium on the plane. Find HH.2 marks
  3. A particle of weight 80 N is in equilibrium, supported by two light inextensible strings. One string has tension T1T_1 N and makes an angle of 30∘30^\circ with the horizontal. The other has tension T2T_2 N and makes an angle of 60∘60^\circ with the horizontal, on the opposite side of the particle.
    By resolving horizontally, show that T2=3 T1T_2=\sqrt{3}\,T_1.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).