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Sequences and recurrence relationsEdexcel International A Level Maths: Flashcards

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What is a recurrence relation?

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What is a recurrence relation?
A rule giving un+1u_{n+1} in terms of unu_n, with a starting value.
What is an increasing sequence?
One with un+1>unu_{n+1}>u_n for all nn.
What is a decreasing sequence?
One with un+1<unu_{n+1}<u_n for all nn.
What is a periodic sequence?
One whose terms repeat in a cycle: un+k=unu_{n+k}=u_n.
What is the order of a periodic sequence?
The number of terms in one cycle.
How do you test if a sequence is increasing?
Show un+1−un>0u_{n+1}-u_n>0 for every nn.
u1=3u_1=3, un+1=2un−1u_{n+1}=2u_n-1. Find u3u_3.
u2=5u_2=5, u3=9u_3=9.
un=n2−6n+10u_n=n^2-6n+10. Find un+1−unu_{n+1}-u_n.
2n−52n-5
What is (−1)n(-1)^n for odd nn and for even nn?
−1-1 for odd nn, +1+1 for even nn.
u1=2u_1=2, un+1=11−unu_{n+1}=\frac{1}{1-u_n}: order?
33 (the terms 2,−1,122,-1,\frac12 repeat).
How do you find u50u_{50} in a periodic sequence of order 44?
50=4×12+250=4\times12+2, so u50=u2u_{50}=u_2.
How do you find constants in un+1=pun+qu_{n+1}=pu_n+q?
Substitute known consecutive terms to form simultaneous equations.

Exam questions on Sequences and recurrence relations

  1. A sequence is given by un=n2−6n+10u_n=n^2-6n+10 for n≥1n\ge1.
    Find an expression for un+1−unu_{n+1}-u_n in terms of nn, and hence state the values of nn for which un+1>unu_{n+1}>u_n.2 marks
  2. A sequence is defined by u1=2u_1=2 and un+1=11−unu_{n+1}=\dfrac{1}{1-u_n} for n≥1n\ge1.
    Find the value of u100u_{100}.2 marks
  3. A sequence has nnth term un=a+b(−1)nu_n=a+b(-1)^n, where aa and bb are constants, u1=3u_1=3 and u2=9u_2=9.
    Find the values of aa and bb.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).