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Newton's laws of motionEdexcel International A Level Maths: Flashcards

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State Newton's first law.

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State Newton's first law.
A particle stays at rest or moves with constant velocity unless a resultant force acts on it.
State Newton's second law.
The resultant force on a particle is F=maF=ma, in the direction of the acceleration.
State Newton's third law.
If A exerts a force on B, B exerts an equal and opposite force on A.
What is the weight of a mass mm?
W=mgW=mg, with g=9.8g=9.8 m s⁻², acting downwards.
Express the newton in base units.
kg m s⁻²
What does a zero resultant force imply?
Constant velocity, or rest: the particle is in equilibrium.
Do Newton's third law force pairs cancel?
No, they act on different bodies.
Does a smooth horizontal plane exert friction?
No; only a normal reaction acts, perpendicular to the plane.
What does a light string imply?
Negligible mass, so the tension is the same throughout.
How do you find acceleration from force written as ai+bja\mathbf{i}+b\mathbf{j}?
Divide each component by the mass: a=F/m\mathbf{a}=\mathbf{F}/m.
Find the magnitude of 3i−4j3\mathbf{i}-4\mathbf{j}.
32+42=5\sqrt{3^2+4^2}=5
State the vector forms of constant acceleration formulae.
v=u+at\mathbf{v}=\mathbf{u}+\mathbf{a}t and r=ut+12at2\mathbf{r}=\mathbf{u}t+\frac12\mathbf{a}t^2
What is speed in terms of velocity?
The magnitude of the velocity vector.
A lift accelerates upwards: how does RR compare with the passenger's weight?
R=mg+maR=mg+ma, so it is greater than the weight.

Exam questions on Newton's laws of motion

  1. A lift of mass 400400 kg carries a passenger of mass 7070 kg. The lift moves vertically upwards with constant acceleration 0.60.6 m s⁻² and is supported by a vertical cable. Take g=9.8g=9.8 m s⁻².
    Find the tension in the cable.2 marks
  2. A particle PP of mass 33 kg moves on a smooth horizontal plane under the action of two forces, (5i−2j)(5\mathbf{i}-2\mathbf{j}) N and (−i+8j)(-\mathbf{i}+8\mathbf{j}) N, only. The vectors i\mathbf{i} and j\mathbf{j} are perpendicular unit vectors in the plane.
    The particle is at rest at time t=0t=0. Find the speed of PP when t=3t=3 s.2 marks
  3. A crate of mass 1515 kg is pulled along a horizontal floor by a rope inclined at 30∘30^\circ above the horizontal. The tension in the rope is 6060 N and the resistance to the motion of the crate is constant at 2020 N. Model the crate as a particle and take g=9.8g=9.8 m s⁻².
    Find the acceleration of the crate.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).